Answer:
your answer is C
Step-by-step explanation:
Answer:
isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.
Step-by-step explanation:
Let denote a set of elements. would denote the set of all ordered pairs of elements of .
For example, with , and are both members of . However, because the pairs are ordered.
A relation on is a subset of . For any two elements, if and only if the ordered pair is in .
A relation on set is an equivalence relation if it satisfies the following:
- Reflexivity: for any , the relation needs to ensure that (that is: .)
- Symmetry: for any , if and only if . In other words, either both and are in , or neither is in .
- Transitivity: for any , if and , then . In other words, if and are both in , then also needs to be in .
The relation (on ) in this question is indeed reflexive. , , and (one pair for each element of ) are all elements of .
isn't symmetric. but (the pairs in are all ordered.) In other words, isn't equivalent to under even though .
Neither is transitive. and . However, . In other words, under relation , and does not imply .
Answer:
x=9
Step-by-step explanation:
5( x + 7) - 3 ( x - 4) = 7x + 2
Distribute
5x+35 - 3x +12 = 7x +2
2x +47 = 7x+2
Subtract 2x from each side
2x+47-2x =7x -2x+2
47 = 5x+2
Subtract 2 from each side
47-2= 5x+2-2
45= 5x
Divide by 5
45/5 =5x/5
9 =x