Answer:
781250 Square Meters
Step-by-step explanation:
Let the dimensions of the rectangular plot be x and y
Farmer Ed wants to enclose three sides of a rectangular plot with a fencing of 2500 meters.
Therefore: Perimeter, P=x+2y=2500
We want to find the largest area that can be enclosed.
Area of the plot, A(x,y)=xy
Substitute x=2500-2y
A(y)=(2500-2y)y
To maximize A, we first find its derivative
The largest area that can be enclosed(at x=1250m,y=625m) is:
1250 X 625
=781250 Square Meters
So the total perimeter of the pasture is 160 ft.. We know that the length of one side is 50 feet. Multiply 50 by 2 because there are 2 sides and subtract that from 160. Now we know that the total of both of the other sides is 60. Divide 60 by 2 to find the width and you find that it is 30 ft. Now multiply 30 by 50 and you get 1500. So the total area of the pasture is 1,500 feet. Hope that helps! :)
8x9= 72 bags of cookies all together.
Well you would have to count the points from the lines and then you had to do a^2+b^2=c^2 and then square the answer
Just subtract 1/5 from 3/10 and you’ll find your answer