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Elden [556K]
2 years ago
7

A package of 8 notebooks costs $10.80. This equation can be used to determine the cost, n, in dollars, of each notebook in the p

ackage.
8n = 10.80

What is the cost, in dollars, of each notebook in the package?

Enter your answer in the box.
Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

$1.35

Step-by-step explanation:

8n = 10.80

Divide both sides by 8 to get n alone.

n = 10.80/8 = $1.35

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Kiera wants to increase her savings account to a balance of $1,350. Her current balance is $174 and she adds $84 a month to her
Yuri [45]
Her goal : 1350

What she has now: 174

she earns 84$ a month

answer is 14 months because 84* 14 is 1176 and if u add 174 $ to that it will give u 1350.
5 0
4 years ago
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Please help will give brainliest i need this its due wednesday and there are like 45-50 questions
creativ13 [48]

Answer:

i think its a

Step-by-step explanation:

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8 0
3 years ago
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Solve each equation. Check your solution. <br> A) -6a=36<br> B) -9d=-72
vovikov84 [41]
A) -6a = 36

Divide both sides by -6 so that (a) is isolated.

a = -6

Check by plugging in -6 for a.

-6a=36

-6(-6)=36

36=36

So, a=-6

B) -9d=-72

Divide both sides by -9.

d = -72/-9

d = 8

Check work by plugging in 8 for d.

-9d=-72

-9(8)=-72

-72=-72

So, d=8

~Hope I helped!~
3 0
3 years ago
What’s the answer to this
dangina [55]

Answer:

c

Step-by-step explanation:

y is equal to 6 multiplied by IxI

for example, if x was 1 the coordinates would be (1,6).

The pattern going (1,6) , (2,12) , (3,18) and so on.

3 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
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