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Dima020 [189]
3 years ago
13

The element whose atomic number is 13 has how many valence electrons electron configuration

Chemistry
1 answer:
RideAnS [48]3 years ago
4 0
It is in Group 3A = 3 valence electrons

Electron Config. = 1s2 2s2 2p6 3s2 3p1
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Dinosaur is older.

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Chemical name for organic compound CH2= CHCH2 CH2 CH2 CH3
kolbaska11 [484]

Answer:

The IUPAC name of the given compound is Pent-1-ene.

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Explanation:

5 0
4 years ago
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

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For ice:

Mass = x g

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Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
4 years ago
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Rzqust [24]

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6 0
3 years ago
1. Which is not true of binary compounds?
nignag [31]
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