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zheka24 [161]
3 years ago
5

Calculate the mass-to-mass ratio of 25.0 g of salt in 105 g of water. Work must be shown in order to earn credit.

Chemistry
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

0.23

Explanation:

  • It is known that, the mass to mass ratio of the salt to water

= (mass of salt / mass of water)

= (25.0 g / 105.0 g)

= 0.23

  • So, the answer is 0.23

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Proportional tax<br> regressive tax<br> progressive tax
Crazy boy [7]

I am sorry can you explain it more?

3 0
3 years ago
Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.
Tanzania [10]

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

  • The structure of the molecule will be as shown in the attached image.
  • The molecular formula of the compound is C₆H₁₂.
  • It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
  • The ring consist of 3 C atoms, so its name is cyclo propane.
  • We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
  • <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

3 0
3 years ago
You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acetate plus acetate concentration
vovangra [49]

<u>Ans: Acetic acid = 90.3 mM and Sodium acetate = 160 mM</u>

Given:

Acetic Acid/Sodium Acetate buffer of pH = 5.0

Let HA = acetic acid

A- = sodium acetate

Total concentration [HA] + [A-] = 250 mM ------(1)

pKa(acetic acid) = 4.75

Based on Henderson-Hasselbalch equation

pH = pKa + log[A-]/[HA]

[A-]/[HA] = 10^(pH-pKa) = 10^(5-4.75) = 10^0.25 = 1.77

[A-] = 1.77[HA] -----(2)

From (1) and (2)

[HA] + 1.77[HA] = 250 mM

[HA] = 250/2.77 = 90.25 mM

[A-] = 1.77(90.25) = 159.74 mM



7 0
3 years ago
Determine the mole ratio between oxygen and water for the following equation:
vodka [1.7K]

Answer:2.2

Explanation:

5 0
2 years ago
A sample of a compound contains 3.21 g of sulfur and 11.4 g of fluorine. Which of the following represents the empirical formula
Sergeeva-Olga [200]

Answer:

The empirical formula is SF6 (option E)

Explanation:

Step 1: Data given

Mass of sulfur = 3.21 grams

Mass of fluorine = 11.4 grams

Molar mass sulfur = 32.065 g/mol

Molar mass fluorine = 19.00 g/mol

Step 2: Calculate moles

Moles = mass /molar mass

Moles sulfur = 3.21 grams / 32.065 g/mol

Moles sulfur = 0.100 moles

Moles fluorine = 11.4 grams / 19.00 g/mol

Moles fluorine = 0.600 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.100 / 0.100 = 1

F : 0.600 / 0.100 = 6

The empirical formula is SF6 (option E)

7 0
3 years ago
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