All categories

2 years ago

If 8.63 grams of Aluminum oxide react with Nitric acid, how many grams of water will be produced?

1 answer:

8 0

Taking into account the reaction stoichiometry, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Al₂O₃ + 6 HNO₃ → 2 Al(NO₃)₃ + 3 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al₂O₃: 1 mole
HNO₃: 6 moles
Al(NO₃)₃: 2 moles
H₂O: 3 moles

The molar mass of the compounds is:

Al₂O₃: 102 g/mole
HNO₃: 63 g/mole
Al(NO₃)₃: 213 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al₂O₃: 1 mole ×102 g/mole= 102 grams
HNO₃: 6 moles ×63 g/mole= 378 grams
Al(NO₃)₃: 2 moles ×213 g/mole= 426 grams
H₂O: 3 moles ×18 g/mole= 54 grams

<h3>Mass of water formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 102 grams of Al₂O₃ form 54 grams of H₂O, 8.63 grams of Al₂O₃ form how much mass of H₂O?

$mass H_{2} O=\frac{8.63 grams of Al_{2} O_{3} x54 grams of H_{2} O}{102 grams of Al_{2} O_{3}}$

<u><em>mass of H₂O= 4.57 grams</em></u>

Then, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

You might be interested in

4. Shows each line represented as a pair of

tankabanditka [31]

If i’m being honest i’m not exactly sure

8 0

3 years ago

What does the octet rule state that explains why atoms bond

dezoksy [38]

The octet rule is a chemical rule of thumb that reflects observation that atoms of main-group elements tend to combine in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas. The rule is especially applicable to carbon, nitrogen, oxygen, and the halogens, but also to metals such as sodium or magnesium.

The valence electrons can be counted using a Lewis electron dot diagram as shown at the right for carbon dioxide. The electrons shared by the two atoms in a covalent bond are counted twice, once for each atom. In carbon dioxide each oxygen shares four electrons with the central carbon, two (shown in red) from the oxygen itself and two (shown in black) from the carbon. All four of these electrons are counted in both the carbon octet and the oxygen octet.

4 0

3 years ago

Read 2 more answers

Which best describes sodium chloride (NaCl)?

OverLord2011 [107]

Answer: NaCl is an ionic compound

Explanation: Sodium Chloride is formed from Na+ and Cl- ions.

It is soluble in water, it has crystalline structure, it has high melting point and

It is insulator as solid form. Water solution leads current.

4 0

3 years ago

What are the coefficients?

jenyasd209 [6]

The numbers in front of the formulas

5 0

3 years ago

In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant

BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

In another experiment, if 80 $XO_3$ molecules react with 104 $BrZ_3$ molecules. How many $Br_2$ molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of $BrZ_3$ react with 6 molecule of $XO_3$

So, 104 molecules of $BrZ_3$ react with $\frac{104}{8}\times 6=78$ molecule of $XO_3$

From this we conclude that, $XO_3$ is an excess reagent because the given moles are greater than the required moles and $BrZ_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of $Br_2$

From the reaction, we conclude that

As, 8 molecules of $BrZ_3$ react to give 4 molecules of $Br_2$

So, 104 molecules of $BrZ_3$ react to give $\frac{104}{8}\times 4=52$ molecules of $Br_2$

Hence, the number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

4 0

3 years ago