If 8.63 grams of Aluminum oxide react with Nitric acid, how many grams of water will be produced?
1 answer:
Taking into account the reaction stoichiometry, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
Al₂O₃ + 6 HNO₃ → 2 Al(NO₃)₃ + 3 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Al₂O₃: 1 mole
- HNO₃: 6 moles
- Al(NO₃)₃: 2 moles
- H₂O: 3 moles
The molar mass of the compounds is:
- Al₂O₃: 102 g/mole
- HNO₃: 63 g/mole
- Al(NO₃)₃: 213 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Al₂O₃: 1 mole ×102 g/mole= 102 grams
- HNO₃: 6 moles ×63 g/mole= 378 grams
- Al(NO₃)₃: 2 moles ×213 g/mole= 426 grams
- H₂O: 3 moles ×18 g/mole= 54 grams
The following rule of three can be applied: if by reaction stoichiometry 102 grams of Al₂O₃ form 54 grams of H₂O, 8.63 grams of Al₂O₃ form how much mass of H₂O?
<u><em>mass of H₂O= 4.57 grams</em></u>
Then, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.
Learn more about the reaction stoichiometry:
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passively diffuses down its concentration gradient through the endothelial cell plasma membrane out of the cell and then passiveley diffuses through the plasma membrane into the cytoplasm of the smooth muscle cell, where it acts to decrease contraction.
Explanation:
Hello,
At first, we must consider that and
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passively diffuses through membranes. As it is produced by an enzyme and accumulates in the endothelial cell cytosol,
passively diffuses down its concentration gradient through the endothelial cell plasma membrane out of the cell and then passiveley diffuses through the plasma membrane into the cytoplasm of the smooth muscle cell, where it acts to decrease contraction.
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