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loris [4]
1 year ago
7

If 8.63 grams of Aluminum oxide react with Nitric acid, how many grams of water will be produced?

Chemistry
1 answer:
Tems11 [23]1 year ago
8 0

Taking into account the reaction stoichiometry, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Al₂O₃ + 6 HNO₃  → 2 Al(NO₃)₃ + 3 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al₂O₃: 1 mole
  • HNO₃: 6 moles  
  • Al(NO₃)₃: 2 moles
  • H₂O: 3 moles

The molar mass of the compounds is:

  • Al₂O₃: 102 g/mole
  • HNO₃: 63 g/mole
  • Al(NO₃)₃: 213 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al₂O₃: 1 mole ×102 g/mole= 102 grams
  • HNO₃: 6 moles ×63 g/mole= 378 grams
  • Al(NO₃)₃: 2 moles ×213 g/mole= 426 grams
  • H₂O: 3 moles ×18 g/mole= 54 grams

<h3>Mass of water formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 102 grams of Al₂O₃ form 54 grams of H₂O, 8.63 grams of Al₂O₃ form how much mass of H₂O?

mass H_{2} O=\frac{8.63 grams of Al_{2} O_{3} x54 grams of H_{2} O}{102 grams of Al_{2} O_{3}}

<u><em>mass of H₂O= 4.57 grams</em></u>

Then, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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What is the molality of an aqueous KCl solution with a mole fraction of KCl, XKCl = 0.175? (The molar mass of KCl = 74.55 g/mol
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Answer:

The molality of the KCl solution is 11.8 molal

Explanation:

Step 1: Data given

Mol fracrion KCl = 0.175

Molar mass KCl = 74.55 g/mol

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mol fraction H2O

mol fraction H2O = 1 - 0.175 = 0.825

Step 3: Calulate mass of H2O

Suppose the total moles = 1.0 mol

Mass H2O = moles H2O * molar mass

Mass H2O = 0.825 * 18.02 g/mol

Mass H2O = 14.87 grams = 0.01487 kg

Step 4: Calculate molality

Molality KCl = 0.175 / 0.01487 kg

Molality KCl = 11.8 molal

The molality of the KCl solution is 11.8 molal

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. a large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is sub
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The large piece of jewelry  that has a mass of 132.6 g and when is submerged in a graduated cylinder that initially contains 48.6 ml water and the volume increases to 61.2 ml once the piece of jewelry is submerged, has a density of: 10.523 g/ml

To solve this problem the formulas and the procedures that we have to use  are:

  • v = v(f)-v(i)
  • d = m/v

Where:

  • d= density
  • m= mass
  • v= volume
  • v(f) = final volume
  • v(i) = initial volume

Information about the problem:

  • m = 132.6 g
  • v(i) = 48.6 ml
  • v(f) = 61.2 ml
  • v = ?
  • d =?

Applying the volume formula we get:

v = v(f)-v(i)

v = 61.2 ml - 48.6 ml

v = 12.6 ml

Applying the density  formula we get:

d = m/v

d = 132.6 g/12.6 ml

d = 10.523 g/ml

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

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