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loris [4]
2 years ago
7

If 8.63 grams of Aluminum oxide react with Nitric acid, how many grams of water will be produced?

Chemistry
1 answer:
Tems11 [23]2 years ago
8 0

Taking into account the reaction stoichiometry, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Al₂O₃ + 6 HNO₃  → 2 Al(NO₃)₃ + 3 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al₂O₃: 1 mole
  • HNO₃: 6 moles  
  • Al(NO₃)₃: 2 moles
  • H₂O: 3 moles

The molar mass of the compounds is:

  • Al₂O₃: 102 g/mole
  • HNO₃: 63 g/mole
  • Al(NO₃)₃: 213 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al₂O₃: 1 mole ×102 g/mole= 102 grams
  • HNO₃: 6 moles ×63 g/mole= 378 grams
  • Al(NO₃)₃: 2 moles ×213 g/mole= 426 grams
  • H₂O: 3 moles ×18 g/mole= 54 grams

<h3>Mass of water formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 102 grams of Al₂O₃ form 54 grams of H₂O, 8.63 grams of Al₂O₃ form how much mass of H₂O?

mass H_{2} O=\frac{8.63 grams of Al_{2} O_{3} x54 grams of H_{2} O}{102 grams of Al_{2} O_{3}}

<u><em>mass of H₂O= 4.57 grams</em></u>

Then, 4.57 grams of H₂O are formed when8.63 grams of Al₂O₃ reacts with HNO₃.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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Explanation:

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

Hence, calculate the molarity of given solution as follows.

     Molarity of citric acid = \frac{\text{mass of citric acid}}{\text{molar mass of citric acid}} \times \frac{1}{\text{volume of solution(L)}}

                                 = \frac{25 g}{192.13 g/mol} \times \frac{1}{0.75 L}

                                 = 0.173 M

As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.

          Normality = Molarity × no. of hydrogen or hydroxide ions

                            = 0.173 × 3

                            = 0.519 N

Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.

3 0
3 years ago
42.9 liters of hydrogen are collected over water at 76.0 °C and has a pressure of 294 kPa. What would the pressure (in kPa) of t
BabaBlast [244]

Answer:

494.1 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 294 kPa

P2 = ?

V1 = 42.9 liters

V2 = 22.8 liters

T1 = 76.0°C = 76 + 273 = 349K

T2 = 38.7°C = 38.7 + 273 = 311.7K

294 × 42.9/349 = P2 × 22.8/311.7

12612.6/349 = 22.8 P2/311.7

36.14 = 22.8P2/311.7

Cross multiply

36.14 × 311.7 = 22.8P2

11264.605 = 22.8P2

P2 = 11264.605 ÷ 22.8

P2 = 494.1 kPa

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2 years ago
According to the law of conservation of mass the mass of reactants will be _____to the mass of products
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Equal. Good luck with other questions!
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The key elements of geosphere are trees, rocks, and dirt.<br><br> True or False
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A sample of CO2 gas has a volume of 2.7 L at 78.5 kPa. At what pressure would this sample of gas have a volume of 4.0L? Temperat
lisabon 2012 [21]

Answer:

52.99 kPa

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Final Volume V2 = 4.0L

Final Pressure P2 = ?

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The relationship between these quantities is given by the mathematical expression of Boyles law. This is given as;

V1P1 = V2P2

P2 = V1P1 / V2

P2 = 2.7 * 78.5 /  4.0

P2 = 52.99 kPa

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