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3 years ago

How do the ionic radii vary within a group of non-metals?

Chemistry

1 answer:

stellarik [79]3 years ago

8 0

Answer: Ionic radii is half the distance between two ions.

Explanation: from top to bottom down an element group, ionic radius increases. This is because a new electron shell is added as you move down the periodic table.

Might Be wrong not sure :)

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In a reaction to make ethyl acetate, 25.5 g CH3COOH react with 11.5 g C2H5OH to give a yield of 17.6 g CH3COOC2H5-

Yakvenalex [24]

Frey red. S dc
;c. B

4 0

2 years ago

iron reacts with sulfur to form iron sulfide. If 60 grams of iron reacts with sulfur to produce 90 grams of iron sulfide how muc

alisha [4.7K]

Answer:

34.44 g.

Explanation:

The balanced equation for the reaction is:

Fe + S → FeS,

It is clear that 1.0 mol of Fe reacts with 1.0 mol of S to produce 1.0 mol FeS.

We need to calculate the no. of moles of 60 grams of iron and 90 grams of iron sulfide:

no. of moles of Fe = mass/atomic mass = (60.0 g)/(55.845 g/mol) = 1.074 mol.

no. of moles of FeS = mass/molar mass = (90.0 g)/(87.91 g/mol) = 1.024 mol.

∵ Fe reacts with S with (1: 1) molar ratio.

∴ The no. of moles of S needed to react with Fe is 1.074 mol.

∴ The no. of grams of S needed = no. of moles x molar mass = (1.074 mol)(32.065 g/mol) = 34.44 g.

8 0

3 years ago

Read 2 more answers

A hypothetical element consists of four isotopes. Use the information below to calculate the average atomic volume mass of the e

Keith_Richards [23]

Answer:

104.969 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 107.977 amu

Abundance (A%) = 0.1620%

Isotope B:

Mass of B = 106.976 amu

Abundance (B%) = 1.568%

Isotope C:

Mass of C = 105.974 amu

Abundance (C%) = 47.14%

Isotope D:

Mass of D = 103.973 amu

Abundance (D%) = 51.13%

Average atomic mass =?

The average atomic mass of the element can be obtained as follow:

Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]

Average atomic mass = [(107.977 × 0.1620)/100] + [(106.976 × 1.568)/100] + [(105.974 × 47.14)/100] + [(103.973 × 51.13)/100]

= 0.175 + 1.677 + 49.956 + 53.161

= 104.969 amu

Therefore, the average atomic mass of the element is 104.969 amu.

8 0

3 years ago

An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha

dlinn [17]

Answer:

Molarity of sodium acetate you will need to add is 0.0324M

Explanation:

Assuming volume of the buffer is 1L.

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

Where pKa is pKa of the weak acid, [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid

Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

[Acetic Acid] = 0.010mol / 1L = 0.010M

And you require a pH of 5.27:

5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

3.236 = [Sodium Acetate] / [0.010M]

3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

<h3>Molarity of sodium acetate you will need to add is 0.0324M</h3>

7 0

3 years ago

Why is light a wave?

madreJ [45]

Answer:

an electromagnetic wave

Explanation:

6 0

3 years ago