Answer:
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
Explanation:
An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.
In this reaction, aqueous sodium hydroxide reacts with aqueous formic acid to form sodium formate and water.
1. Molecular equation
HCHO₂(aq) + NaOH(aq) ⟶ NaCHO₂(aq) + H₂O(ℓ)
2. Ionic equation
Sodium hydroxide and sodium formate are soluble ionic compounds, so we write them as hydrated ions.
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
Answer:
This question has no options but it can be answered based on the understanding of the function of ribosomes.
The effect is the deficiency of proteins in the cell.
Explanation:
Ribosomes are one of the most important cellular organelles found in living organisms. Infact, they are so important that they are found in both the prokaryotic and eukaryotic cell. Ribosome functions in PROTEIN SYNTHESIS as they are the site where the mRNA encoding protein building blocks (amino acids) undergo their translational process.
According to this question, an analyzed cell is found to be missing most of its ribosomes. This means that the function performed by the missing organelle, which is SYNTHESIS OF PROTEINS, will be lacking. Hence, that particular cell will be PROTEIN-DEFICIENT.
Answer:
Li2SO4
Explanation:
Balance the reaction of Li3PO4 + MgSO4 = Li2SO4 + Mg3(PO4)2 using this chemical equation balancer!
Answer: Melting point and boiling point
Explanation:
Chemical Reaction
There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
Learn more about number of moles at: brainly.com/question/1542846
