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2 years ago

What is 2/8 in its simplest form

Mathematics

2 answers:

arlik [135]2 years ago

4 0

It’s 1/4

2/8. First find the highest number that goes into it which is 2.
2/2=1
8/2=4
1/4

Mumz [18]2 years ago

3 0

Answer:

Step-by-step explanation: because you find a common number that both the numerator and the denominator can be divided by. In this case, it is 2 . You can't divide 14 anymore so that is the final answer.

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Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro

topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation $ax^2+bx+c=0$ :

$\Delta=b^2-4ac$

If Δ < 0, then the equation has two complex roots $x=\dfrac{-b\pm\sqrt\Delta}{2a}$

If Δ = 0, then the equation has one repeated root $x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}$

$1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56$

$3.\ 2x^2+x-6=0\\\\a=2,\ b=1,\ c=-6\\\\\Delta=1^2-4(2)(-6)=1+48=49>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt{49}=7\\\\x=\dfrac{-1\pm7}{(2)(2)}\\\\x_1=\dfrac{-8}{4}=-2,\ x_2=\dfrac{6}{4}=\dfrac{3}{2}\\\\==============================\\\\4.\ 13x^2-4=0\qquad\text{add 4 to both sides}\\\\13x^2=4\qquad\text{divide both sides by 13}\\\\x^2=\dfrac{4}{13}\to x=\pm\sqrt{\dfrac{4}{13}},\ \bold{two\ distinct\ roots}\\\\==============================$

$5.\ x^2-6x+16=0\\\\a=1,\ b=-6,\ c=16\\\\\Delta=(-6)^2-4(1)(16)=36-64=-28$

$7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}$

6 0

3 years ago

Read 2 more answers

The first term of a geometric series is 124. The sum to infinity is 64 . Find the common ratio

zalisa [80]

9514 1404 393

Answer:

-15/16

Step-by-step explanation:

The sum of a geometric series with first term a1 is ...

S = a1/(1 -r)

Then the common ratio (r) is ...

r = 1 -a1/S

For the given values, the ratio is ...

r = 1 - 124/64 = -15/16

The common ratio is -15/16.

7 0

3 years ago

Oscar says to Vanesa: "I am five times the age you were when I was the age you are; and when you are the age I am, our ages will

Gemiola [76]

Answer:

Vanessa is 60 and the other person is 12

Step-by-step explanation:

X + 5x = 72

6x = 72

x = 12

12 x 5 = 60

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the other person is 12

60 + 12 = 72

3 0

3 years ago

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Which is true about this division problem? Select all

worty [1.4K]

Answer:

45 does not go into 285 evenly

The quotient contains a repeating decimal

The quotient is 6.3

Step-by-step explanation:

285/45 = 6.33333333

6.33333333 = 6.3

3 0

4 years ago

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Does (0,0) satisfy x+3y>3

PtichkaEL [24]

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4 0

3 years ago