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3 years ago

9

Maggie has a bag of coins (8 nickels, 6 quarters, 12 dimes, 20 pennies). If she picks a coin at random, what is the probability

that she will pick a quarter?

1 answer:

snow_tiger [21]3 years ago

3 0

Answer:

Step-by-step explanation:

Add the all up that will give you a denomator then 6 is the numerator

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The following function represents the production cost f(x), in dollars, for x number of units produced by company 1:

solniwko [45]

Answer:

The answer is confirmed 1. Just took it.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The line of best fit for a scatter plot is shown:

alex41 [277]

In the slope intercept form, b represents the y intercept.
y = mx +- b

Therefore, if the y intercept is at 6, the formula of the line will look like
<span>y=mx + 6
</span>
This eliminates the first two options,
$y = -6x + \frac{3}{4} 
$
and
$y=6x + \frac{3}{4}$

and leaves behind
$y= - \frac{3}{4} +6$
and
$y= \frac{3}{4} x+6$

Since the line you indicated is sloping downwards towards the lower right hand corner. It must have a negative slope.

Therefore, the answer must be the 3rd option.

<span> $y= - \frac{3}{4} +6$ </span>

8 0

3 years ago

Which graph represents all the real numbers, x, where x ≤ 3?

never [62]

shaded arrow to the left.

shaded in circle.

7 0

2 years ago

Fei Yens dog eats 8 ounces of dog food each day. Fei Yen bought a 28 pound bag of dog food. how many 8 ounce servings are in a 2

steposvetlana [31]

One pound is 16 ounces so 28 pounds is 28x16 which is 448. 448 divided by 8 ounces per serving is 56 ounces per bag

4 0

2 years ago

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

1 year ago