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Sedbober [7]
2 years ago
9

Complete the table of values for y=2xsquared+x

Mathematics
1 answer:
hodyreva [135]2 years ago
8 0

The solution of y= 2x^{2} +x given as:

x:   0      1       2       3

y:   0      3      10      21

<h3>What is Linear Equation?</h3>

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

Given function is:

y= 2x^{2} +x

For finding the solution of above expression, take value of x and solve for y.

  • If x=0

y= 2(0)+0

y=0

  • If x=1,

y= 2(1)^{2} +1= 3

  • If x=2

y=2(2)^{2} +2=10

  • If x=3

y= 2(3)^{2} +3=21

The required table is:

x:   0      1       2       3

y:   0      3      10      21

Learn more about linear equation here:

brainly.com/question/488051

#SPJ1

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borishaifa [10]

Answer: As a fraction, the answer is 3/8 (because 5/8 - 2/8 = 3/8). As a whole number, 3/8ths can be represented by 0.375 (as 0.375 is equal to 3/8). :)

3 0
3 years ago
Read 2 more answers
Please HELP!! It’s due today
Aleks04 [339]

Answer:

For C all she has to do is look at the chart-

0=0

1=4

2=8

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4=16

4 0
3 years ago
I need help one this question how do you Factor 75 - 95.
Luba_88 [7]

Answer:

+-(1,2,4,5,10,20)

Step-by-step explanation:

well if this is factors of -20 (bc 75-95=-20)

then it will be +-(1,2,4,5,10,20)

3 0
3 years ago
7=100z what does z equal?
UNO [17]

Answer:

z = 7/100

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Couple has got 5 children , what is the probability of have 3girls and 2 boys ?
Delicious77 [7]
5 children so you have 2^5=32 possibilities to "assign" genders
P(3 girls):
how many possibilities are there to "assign" the 3 girl-genders to the 5 children? the first girl has 5 possibilities then the next 4, 3 -> 5*4*3=60
but these possibilities include orders of assigned genders, while children 1-5 might differ the gender "girl" is always the same so we have the remove the orderings of the 3 girl-gender assignments which is 3*2*1=6
if we divide 60/6 we get 10 possibilities to have 3 girls, so what is the resulting chance? the 10 possibilities divided by the total 32 possibilities: 10/32=5/16=P(3 girls)=P(2 boys)

this is a bit of lengthy way of saying "use the binomial coefficient" equation/explaining it a bit which is (n!)/(k!(n-k)!) with n=5, k=3:
5*4*3*2*1/((3*2*1)*(2*1))=
5*4*3*2/(3*2*2)=
5*4*3*2/(3*4)=
5*2=
10 possibilities again


P(girls>=4)=P(boys<=1)=P(boys=1)+P(boys=0)
(or P(girls=4)+P(girls=5))

P(boys=0) is the easy case: simply multiply the chance of getting a girl 5 times: (1/2)^5=1/32
P(boys=1)= again the binomial coefficient with n=5 and k=1:
5*4*3*2*1/((1)*(4*3*2*1))=
5*4*3*2/(4*3*2)=
5 possibilities
so the P(boys=0)=1 possibility + P(boys=1)=5 possibilities totals to 6 possibilities
again the chance is the 6 possibilities divided by all 32 possibilities: 6/32=3/16

P(alternate gender starting with boy): when thinking about the possibilities then there is only a single way to build that order: bgbgb, so one possibility
knowing there is only one way we already know P(alternate...)=1/32 by again dividing by the total amount of possibilities
the alternative way would be to multiply P(boy)*P(girl)*P(boy)*P(girl)*P(boy)=(1/2)^5= 1/32 again





5 0
3 years ago
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