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victus00 [196]
3 years ago
6

Classify each polynomial by its degree and number of terms

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0
You have that:

 1) 7x/4+3 (Name using degree: First degree polynomial),(Name using number of terms:binomial)

 2) 5.2x^2-4x+2.5 (Name using degree: Quadratic polynomial),(Name using number of terms:trinomial)

 3) 3/5 (Name using degree: zero degree polynomial),(Name using number of terms:monomial)

 4) 0.75x^2 (Name using degree: Quadratic degree polynomial),(Name using number of terms:monomial).
r-ruslan [8.4K]3 years ago
3 0

Answer with explanation:

We know that a polynomial is classified <u>based on the degree</u> as follows:

Constant-

If it has a degree zero.

and the equation of such a polynomial is:

   p(x)=a

Linear--

It has degree 1.

and the equation of such a polynomial is:   p(x)=ax+b

Quadratic--

If it has degree two and the equation of the polynomial is given by:

     p(x)=ax^2+bx+c

<u>Based on number of Terms--</u>

Monomial--

If it has just one term.

Binomial--

If it has two terms.

Trinomial--

If it has three terms.

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Any help would be great!
Elina [12.6K]

Answer:

g(x) = (x + 3)²

Step-by-step explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

here (h, k ) = ( - 3, 0 ) , then

g(x) = (x - (- 3))² + 0 , that is

g(x) = (x + 3)²

8 0
2 years ago
What is the interquartile range of the data set? 23, 35, 55, 61, 64, 67, 68, 71, 75, 94, 99
Marina86 [1]
99 94 75 71 68 67 64 61 55 35 23
7 0
3 years ago
Read 2 more answers
What are the solutions of the equation x^6-9x^3+8=0
Triss [41]

USE CALCULATOR!!! EPLAINT OOOO

4 0
3 years ago
Suppose that y = k * (x - 1/3) ^ 2 is a parabola in the xy -plane that passes through the point (2/3, 1) :Find k and the length
Dennis_Churaev [7]

Answer:

k = 9

length of chord = 2/3

Step-by-step explanation:

Equation of parabola:   y=k (x-\frac13)^2

<u />

<u>Part 1</u>

If the curve passes through point (\frac23 ,1), this means that when x=\dfrac23, y = 1

Substitute these values into the equation and solve for k:

\implies 1=k \left(\dfrac23-\dfrac13\right)^2

\implies 1=k \left(\dfrac13 \right)^2

Apply the exponent rule \left(\dfrac{a}{b} \right)^c=\dfrac{a^c}{b^c} :

\implies 1=k \left(\dfrac{1^2}{3^2} \right)

\implies 1=\dfrac{1}{9}k

\implies k=9

<u>Part 2</u>

  • The chord of a parabola is a line segment whose endpoints are points on the parabola.  

We are told that one end of the chord is at (\frac23 ,1) and that the chord is horizontal.  Therefore, the y-coordinate of the other end of the chord will also be 1.  Substitute y = 1  into the equation for the parabola and solve for x:

\implies 1=9 \left(x-\dfrac13 \right)^2

\implies \dfrac19 = \left(x-\dfrac13 \right)^2

\implies \sqrt{\dfrac19}  = x-\dfrac13

\implies \pm \dfrac13  = x-\dfrac13

\implies x=\dfrac23, x=0

Therefore, the endpoints of the horizontal chord are: (0, 1) and (2/3, 1)

To calculate the length of the chord, find the difference between the x-coordinates:  

\implies \dfrac23-0=\dfrac23

**Please see attached diagram for drawn graph. Chord is in red**

6 0
2 years ago
Molly uses 192 beads to make a bracelet and a necklace. It takes 5 times as many beads to make a necklace than t does to make a
neonofarm [45]
Solve for the bracelet first. x represents number of beads for bracelet So it would be number of beads for the bracelet + number of beads for necklace (5x) and they both equal 192 x + 5x = 192 Then you would add the x and 5x.<br />6x = 192 Now all you have to do is divide by 6 on both sides. 6× ÷ 6 = 192 ÷ 6 You know have the number of beads it takes for a bracelet. x = 32 to get the necklace all you need to do is multiply it by 5 because you need 5 times more for the necklace. 32 × 5 total beads needed is 160. 160 x+5x=192 6×=192 6x÷6=192÷6 x=32 necklace needs 32x5 beads per necklace is 160
7 0
4 years ago
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