Can someone teach me how to do this?
no files or links please
1 answer:
Check the picture below.
we know the box has a square base, meaning the Length = Width, we also know its volume is 400 times its height.
![\textit{volume of a rectangular prism}\\\\ V=Lwh~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=h+12\\ w=h+12\\ V=400h \end{cases}\implies 400h=(h+12)(h+12) \\\\\\ 400h=\stackrel{F~O~I~L}{h^2+24h+144}\implies 0=h^2+24h-256 \\\\\\ 0=(h-8)(h+32)\implies h= \begin{cases} 8~~\checkmark\\ -32 \end{cases}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20rectangular%20prism%7D%5C%5C%5C%5C%20V%3DLwh~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20L%3Dh%2B12%5C%5C%20w%3Dh%2B12%5C%5C%20V%3D400h%20%5Cend%7Bcases%7D%5Cimplies%20400h%3D%28h%2B12%29%28h%2B12%29%20%5C%5C%5C%5C%5C%5C%20400h%3D%5Cstackrel%7BF~O~I~L%7D%7Bh%5E2%2B24h%2B144%7D%5Cimplies%200%3Dh%5E2%2B24h-256%20%5C%5C%5C%5C%5C%5C%200%3D%28h-8%29%28h%2B32%29%5Cimplies%20h%3D%20%5Cbegin%7Bcases%7D%208~~%5Ccheckmark%5C%5C%20-32%20%5Cend%7Bcases%7D)
now, notice, -32 is a valid value for "h", however, the height cannot be a negative value, so we toss that root/solution.

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