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3 years ago

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In type form the report is about 3 pages long. How many words long is tour report . if your book report is 4 pages long and at a

steady rate of 20 words per minute it takes you 48 minutes.

1 answer:

Sliva [168]3 years ago

6 0

Do 48 x 20 which is 960

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Ok so i thought i knew what i was doing but then i didn't know what i was doin-

Butoxors [25]

Answer:

uh pretty sure the answer is C

7 0

3 years ago

Read 2 more answers

4y + x = 12, 2x = 24 - 8y<br> Solve by Substitution

Ann [662]

Answer: Undefined

Step-by-step explanation:

4y+x=12, 2x=24-8y

Isolate x by subtracting 4y

4y+x=12

x=12-4y

Plug the equation for x in to anywhere you see the variable x in the other equation

2(12-4y)=24-8y

Distribute 2

24-8y=24-8y

Get the variables on one side so add 8y (cancels out)

24=24

Can’t solve its undefined

4 0

3 years ago

How do i solve x/2+1/3=x/3+1/2

stepladder [879]

X/2+1/3=x/3+1/2
x/2=x/3+1/2-1/3
x/2 - x/3 = 3/6 - 2/6
x/2 - x/3 = 1/6
3x/6 - 2x/6 = 1/6
x/6 = 1/6
x = 1/6 * 6

x = 1

8 0

3 years ago

Read 2 more answers

You buy 88 packs of markers with 2020 markers in each pack. You already had 1010 markers. Which equation shows how to calculate

alexgriva [62]

You would multiply 2020×88=177760
then add 177760+1010=178770
my calculations came out as 178770

5 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

3 years ago