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ankoles [38]
3 years ago
13

What is the length of the unknown side of this triangle?

Mathematics
2 answers:
pychu [463]3 years ago
6 0

Answer:

shoto its me deku!!!!!!

almond37 [142]3 years ago
4 0

Answer:

65

Step-by-step explanation:

<em>first we know that it is a right angle and its 90 degrees.</em>

<em>now we add up the angles it has givin us.</em>

<em>17 plus 8 = 25</em>

<em>90 minus 25 = 65.</em>

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Gemiola [76]

Answer:  (D) <em>bottom right graph</em>

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: f(x) = a(x - h)² + k,    where

  • (h, k) is the vertex
  • |a| is the vertical stretch
  • sign of "a" determines the direction of the parabola

Given g(x) = (x - 3)² - 5

  • vertex (h, k) = (3, -5)
  • vertical stretch |a| = 1
  • sign of "a" is positive so parabola points up

The only graph that satisfies all of these conditions is the bottom right.

7 0
3 years ago
Pascal wants to ride his bike to and from school 3 days a week. His house is 2.58 kilometers from his school. How many meters wi
klemol [59]

Answer:

I thi k the answers is 108.36

5 0
3 years ago
Need help with this!!!
fomenos

Answer:

A

(hg)( x)=(4x-3)(x+2)=4x²+5x-6

6 0
3 years ago
15 is what percent of 500
TEA [102]
% of 15 in 500= (15÷500)×100
= 0.03×100
= 3 %
5 0
3 years ago
Prove that the sum of the squares of the lengths of the medians of a triangle is three fourths the sum of the squares of the len
aleksandr82 [10.1K]

Answer:

3[|AB|² + |BC|² + |AC|²] = 4[|AD|² + |BE|² + |CF|²]

Step-by-step explanation:

I've attached an image showing a triangle divided into it's medians.

Now, from the attached image, we see that AB, BC & CD are the lengths of sides of triangle while AD, BE & CF are lengths of the 3 medians of the triangle.

Now, to prove our question, we will use appolonius theorem which states that "the sum of the squares of any of the two sides of a triangle is equal to twice the square on half the third side including twice the square on the median that bisects the third side.

Applying this theorem to the image attached, we have the following;

|AB|² + |AC|² = 2[|AD|² + |BC/2|²]

|AB|² + |BC|² = 2[|BE|² + |AC/2|²]

|AC|² + |BC|² = 2[|CF|² + |AB/2|²]

Adding the 3 equations above gives us;

2|AB|² + 2|BC|² + 2|AC|² = 2|AD|² + |BC|²/2 + 2|BE|² + |AC|²/2 + 2|CF|² + |AB|²/2

Collecting like terms;

(2|AB|² - |AB|²/2) + (2|BC|² - |BC|²/2) + (2|AC|² - |AC|²/2) = 2|AD|² + 2|BE|² + 2|CF|²

Thus gives;

(3/2)[|AB|² + |BC|² + |AC|²] = 2[|AD|² + |BE|² + |CF|²]

Multiply both sides by 2 to give;

3[|AB|² + |BC|² + |AC|²] = 4[|AD|² + |BE|² + |CF|²]

6 0
3 years ago
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