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sasho [114]
3 years ago
15

What is the common difference between the elements of the arithmetic sequence below?

Mathematics
1 answer:
Inga [223]3 years ago
3 0
-36/-31.5 = 1.1428571428571428571428571428571
-31.5/-27 = 1.1666666666666666666666666666667
-27/-22.5 = 1.2
-22.5/-18 = 1.25
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A clothing business finds there is a linear relationship between the number of shirts, Q ,it can sell and the price, P , it can
Vlad [161]

Answer:

P = -0.004Q + 149

Step-by-step explanation:

The general form of the linear equation is:

P=aQ+b

The slope of the equation (a) can be found by using the two given points (4,000; $133) and (27,000; $41)

a = \frac{\$41-\$133}{27,000-4,000}\\a=-0.004

Applying the point (4,000; $133) to the equation below yields in the linear equation for Price as a function of the number of shirts:

P-P_0=a(Q-Q_0)\\P-133=-0.004(Q-4,000)\\P = -0.004Q+149

The linear equation is:

P = -0.004Q + 149

8 0
3 years ago
-2(7a+ 9b) = –14a + [?]b
OverLord2011 [107]

Answer:

-18

Step-by-step explanation:

Left Hand Side = -2(7a + 9b) = -14a - 18b

Comparing it with Right Hand Side, ?  = -18

3 0
3 years ago
Read 2 more answers
Find the length of UV.
katovenus [111]
7x-8 (2) = 12x+8
14x-16 = 12x+8
-12x -12x
2x-16 = 8
+16 +16
2x = 24

÷2 ÷2
x= 12

UV= 7x-8
UV= 7(12)-8
UV= 84-8
UV= 76
7 0
3 years ago
A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
What is the mean of 13,20,15,20
il63 [147K]

Answer:

17

Step-by-step explanation:

all 4 numbers added up, 68, divide by the amount of numbers, which is 4, and you get the answer

8 0
4 years ago
Read 2 more answers
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