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Ksju [112]
2 years ago
15

bryn has a stack of photos measuring 12cm wide and 16 cm high. he wants to display them on a large rectangular poster in such as

way that all photos are equally spaced on each side, including at the edges of the poster, as illustrated. Bryn wants to display 9 photos (with longer side vertical) in 3 rows of 3 photos each with 2cm spacing around each photo. What are the dimensions of the poster?
Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0

The dimensions of the poster will be 16 cm wide and 56 cm high.

<h3>Meaning of Dimension</h3>

Dimension in mathematics can be defined as the measure of the size or distance of an object, or region, space in one direction.

Dimension can simply be defined as the measurement of the length,  height, breadth and width of an object or thing.

In conclusion, The dimensions of the poster will be 16 cm wide and 56 cm high.

Learn more about dimensions:  brainly.com/question/26740257

#SPJ1

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66.6 reoccurring as a fraction .
Setler [38]

Answer:

66 2/3 as a mixed number or 200/3 as an improper fraction.

Step-by-step explanation:

That would be 66 2/3.

0.6 recurring is 2/3.

8 0
3 years ago
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Geometry homework (☉__☉”)
lara [203]

Answer:

7. Always, Veritcal Angle therom

8. Never true, it will never add up to 180 degrees

9. Never true, it will never add up to 90 degrees

10. Never true, Angle 8 and 5 are not vertical with one anouther.

11. Sometimes

12. Yes it is possible.

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3 years ago
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There is a bag of marbles that contains 4 blue marbles, 3 red marbles, 2 green marbles, and 1 brown marble. If one was picked at
Semenov [28]

Answer:

2/15

Step-by-step explanation:

P(B,B) = 4/10 x 3/9

= 2/5 x 1/3 or 2/15

7 0
3 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

8 0
3 years ago
Hey guys!
GaryK [48]

The value of c from the given expression is -

<h3>Function and values</h3>

Given the following function

c(n)= −c(n−1)+1

Given the following parameters

c(1)=3

Substitute

3 = −c(3−1)+1

3 = -2c + 1

-2c = 3-1

-2c = 2

c = -1

Hence the value of c from the given expression is -1

Learn more on equation here: brainly.com/question/2972832

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8 0
1 year ago
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