bryn has a stack of photos measuring 12cm wide and 16 cm high. he wants to display them on a large rectangular poster in such as
1 answer:
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Answer:
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers at most =30/60=0.5
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Step-by-step explanation:
Relative Frequency Frequency x
6/60=0.1 6 0
0.2 12 1
0.2 12 2
0.25 15 3
0.1 6 4
0.05 3 5
0.05 3 6
0.0167 1 7
<u>0.033 2 8</u>
<u>∑ 60 </u>
The number of six non conforming transducers at most
= 6+12+12+15+6+3= 54
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than five non conforming transducers
= 6+12+12+15+6 = 51
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers
2+1+3+3+6+15= 30
The number of at least six non conforming transducers at most =30/60=0.5
We plot the histogram by placing the percentages (or relative frequency *100) on the y –axis and the X on the x-axis.
The center of the histogram is given by the mean of the distribution which in this case is = ∑fx/∑f= 161/60= 2.683
So option d is the best answer
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Because at the center (between 2 and 3) the curve is increasing
