Answer:
x=-50
Step-by-step explanation:
31/25x=-62
x=-62/(31/25)
x=(-62/1)(25/31)
x=--1550/31
x=-50
23,307,609 that is the answer
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer: No, these results are not statistically significant because
p > 0.05
Step-by-step explanation:
The null hypothesis is
H0 : μ = 17
The alternative hypothesis is
H 1 : μ ≠ 17
where μ is the mean amount of cereal in each box.
The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.
If the level of significance is lesser than the p value, we would accept the null hypothesis.
Therefore, the correct option is
No, these results are not statistically significant because p>0.05
