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Montano1993 [528]

3 years ago

13

Marshall has been given the option to receive an allowance once a week or once a month. Should he choose $3.25 each week or $10.

75 eacheck month? Explain.

1 answer:

shutvik [7]3 years ago

3 0

I would choose $3.25 on this because you would be making $13 a month instead of $10.75.

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Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die

Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

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Answer:

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Step-by-step explanation:

this is cuz of the 45 45 90 formula

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Answer:

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Step-by-step explanation:

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The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po

noname [10]

Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

$A = B$

Step-by-step explanation:

<em>See comment for complete question</em>

Given

$A: (4x^2 - 4x)(x^2 - 4)$

$B: (x^2 + x - 2)(4x^2 - 8x)$

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

$A: (4x^2 - 4x)(x^2 - 4)$

Factor out 4x

$A: 4x(x - 1)(x^2 - 4)$

Apply difference of two squares on x^2 - 4

$A: 4x(x - 1)(x - 2)(x+2)$

For, Polynomial B: We have:

$B: (x^2 + x - 2)(4x^2 - 8x)$

Expand x^2 + x - 2

$B:(x^2 + 2x - x - 2)(4x^2- 8x)$

Factorize:

$B:(x(x + 2) -1(x + 2))(4x^2- 8x)$

Factor out x + 2

$B:(x -1) (x + 2)(4x^2- 8x)$

Factor out 4x

$B:(x -1) (x + 2)4x(x- 2)$

Rearrange

$B: 4x(x - 1)(x - 2)(x+2)$

The simplified expressions are:

$A: 4x(x - 1)(x - 2)(x+2)$ and

$B: 4x(x - 1)(x - 2)(x+2)$

Hence, both polynomials are equal

$A = B$

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3 years ago