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3 years ago

14

The runway at New York Fashion Week is 110 feet long. A model walked 3 different outfits by the designed FTL MODA up and down th

e runway. What total distance did she travel?

1 answer:

Sladkaya [172]3 years ago

5 0

110 x 3 =330x2=660 need more words to send

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Please please please help me!! I'll give 5 stars and thanks!

ipn [44]

F(1) = -2

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4 0

4 years ago

What is the angle of B?

amid [387]

Answer:

31

Step-by-step explanation:

4 0

3 years ago

What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm

alekssr [168]

We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm

8 0

3 years ago

Suppose that many large samples are taken from a population and that the

rewona [7]

Answer:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

$\bar X = 0.22$

And the standard error is given by:

$SE = 0.029$

We want to construct a 68% confidence interval so then the significance level would be :

$\alpha=1-0.68 = 0.32$ and $\alpha/2 =0.16$ . The confidence interval is given by:

$\bar X \pm z_{\alpha/2} SE$

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

$z_{\alpha/2}= 1$

And replacing we got:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

5 0

3 years ago

What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal

rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0

3 years ago