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2 years ago

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The half-life of a radioactive kind of neptunium is 2 days. If you start with 736 grams of it, how much will be left after 6 day

s?

1 answer:

stepan [7]2 years ago

8 0

92, if it halves every 2 days for 6 days divide 736 by 2 thrice.

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I know the selected answer is correct but I'm not too sure how to get that answer.

Kryger [21]

$\tt{ Hey \: there , \: Mr.Panda \: ! }$ ;)

♨ $\large{ \tt{ E \: X \: P \: L \: A \: N \: A \: T \: I\: O \: N}}:$

⤻ Before solving the given question , you should know the answer of these questions :

✺How do you find the hypotenuse , perpendicular and base when the angle ( $\theta \: , \alpha \: ,\beta$ ) is given ?

⇾ The longest side , which is the opposite side of right angle is the hypotenuse ( h ). There are two other sides , the opposite and the adjacent. The naming of these sides depends upon which angle is involved. The opposite is the side opposite the angle involved and it is called the perpendicular ( p ) . The adjacent us the side next to the angle involved ( buy not the hypotenuse ) and it is called the base ( b ).

☄ $\large{ \tt{REMEMBER}} :$

$\bf{ \sin \theta = \frac{opposite}{hypotenuse} = \frac{perpendicular}{hypotenuse} }$

$\bf{ \cos\theta = \frac{adjacent}{hypotenuse} = \frac{base}{hypotenuse} }$

$\bf{ \tan \theta = \frac{opposite}{adjacent} = \frac{perpendicular}{base} }$

In the above cases , $\theta$ is taken as the angle of reference.

♪ Our Q/A part ends up here! Let's start solving the question :

❈ $\large{ \tt{GIVEN}} :$

Perpendicular ( p ) = ? , Hypotenuse ( h ) = 18 & base ( b ) = 16

✧ $\large{ \tt{TO \: FIND} : }$

Value of tan $\theta$

✎ $\large{ \tt{SOLUTION}} :$

Firstly , Finding the value of perpendicular ( p ) using Pythagoras theorem :

❃ $\boxed{ \sf{ {h}^{2} = {p}^{2} + {b}^{2} }}$ [ Pythagoras theorem ]

$\large{ ⇢ \sf{p}^{2} + {b}^{2} = {h}^{2} }$

$\large{⇢ \sf{ {p}^{2} = {h}^{2} - {b}^{2} }}$

$\large{ ⇢\sf{ {p}^{2} = {18}^{2} - {16}^{2} }}$

$\large{⇢ \sf{ {p}^{2} = 324 - 256}}$

$\large{⇢ \sf{ {p}^{2} = 68}}$

$\large{⇢ \sf{p = \sqrt{68}}}$

$\large{ ⇢\sf{p = \boxed{ \tt{2 \sqrt{17}}} }}$

Okey, We found out the perpendicular i.e $\tt{2 \sqrt{17}}$ . Now , We know :

❊ $\large{ \sf{ \tan \theta} = \frac{perpendicular}{base} }$

$\large {\tt{↬ \: tan \theta = \frac{2 \sqrt{17} }{16}}}$

$\large{ \tt{ ↬ tan \theta = \frac{ \cancel{2} \: \sqrt{17} }{ \cancel{16} \: \: 8} }}$

$\large{ \tt{ ↬ \boxed{ \tt{tan \theta = \frac{ \sqrt{17} }{8}}}}}$

⟿ $\boxed{ \boxed{ \tt{OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{ \frac{ \sqrt{17} }{8}}}}}}}$

۵ Yay! We're done!

♕ $\large\tt{RULE \: OF \:SUCCESS }:$

Never lose hope & keep on working ! ✔

ツ Hope I helped!

☃ Have a wonderful day / evening! ☼

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3 years ago

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List at least three example of racial injustice that king uses as effective support for his claim that African American are not

Effectus [21]

The following are the list of the racial injustice that king uses as effective support for his claim that african american are not free.
#1. He uses word to contrast the racial situation in the country in the past and present to what is expected in the future,
#2 The king shows that there is hope for change in the future
#3. The king uses metaphor.

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3 years ago

Find the domain and range of the function graphed. Assume that the function has arrows that extend the graph past the screen sho

3241004551 [841]

Put the dot on the 5 and than go down 4 i think this is right but i might be wrong sorry if i am

5 0

3 years ago

Use the rectangle below as an example

velikii [3]

Answer:

sorry man or man drawing a little more about the job than the rest on any of these

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2 years ago

Can somebody pls help I’ll mark brainliest

Mnenie [13.5K]

<span><u><em>Answer:</em></u>
64

<u><em>Explanation:</em></u>
The square of any number can be obtained by multiplied the number by itself.
<u>In other words:</u>
square of x = x</span>²<span> = x * x

For the given, we want to get the square of 8. This means that we will <u>multiply 8 by itself.</u>
Therefore:
square of 8 = 8</span>²<span> = 8 * 8 = 64

Hope this helps :)</span>

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3 years ago

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