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2 years ago

12

The half-life of a radioactive kind of neptunium is 2 days. If you start with 736 grams of it, how much will be left after 6 day

s?

1 answer:

stepan [7]2 years ago

8 0

92, if it halves every 2 days for 6 days divide 736 by 2 thrice.

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Solve by factoring: x^4-12x^2= 64

USPshnik [31]

The final solution is all the values that make <span><span><span><span><span>(<span>x+4</span>)</span><span>(<span>x<span>−4</span></span>)</span></span><span>(<span><span>x2</span>+4</span>)</span></span>=0</span><span><span><span><span>x+4</span>⁢<span>x<span>-4</span></span></span>⁢<span><span>x2</span>+4</span></span>=0</span></span> true.<span>x=<span>−4</span>,4,<span>2i</span>,<span><span>−2</span><span>i</span></span></span>

7 0

3 years ago

Read 2 more answers

What is 3 minutes 56 seconds +42 minutes 28 seconds+34 minutes 34 seconds +39 minutes 9 seconds =

Anna35 [415]

Answer:

2 hours and 7 minutes

Step-by-step explanation:

4 0

3 years ago

Bogdan [553]

Answer:

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: $f(x) = C+ A sinBx$ and $f(x) = C + A cosBx$ . A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or $\frac{2\pi}{|B|}$ . C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is $\frac{2\pi}{|2|}=\pi$

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

3 0

3 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

6 0

3 years ago

Read 2 more answers

The area of a circle is 40 pie (3.14). Find the radius of the circle in simplest form.

dezoksy [38]

Area of a circle equation:
A=(3.14)r^2

40(3.14)=(3.14)*r^2
40=r^2
r= square root of 40

simplified radius is 2 times root 10
(See the photo I attached for the work)

7 0

3 years ago