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Novay_Z [31]
2 years ago
6

Line segment EF begins at (-1,5) and ends at (-1, -3). The segment is translated to the right 4 units and down

Mathematics
1 answer:
nignag [31]2 years ago
4 0

The coordinates for the line segment E'F' are (3, 3) and (3, -5) and the length of the segment E'F' is 8 units.

<h3>What is geometric transformation?</h3>

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

Line segment EF begins at (-1, 5) and ends at (-1, -3). The segment is translated right 4 units and down 2 units to form line segment E'F'. Then the coordinate of E' and F' will be:

E' = (-1 + 4, 5 – 2) = (3, 3)

F' = (-1 + 4, -3 - 2) = (3, -5)

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of the E'F' = √(0 + 64) = 8 units

Thus, the coordinates for the line segment E'F' are (3, 3) and (3, -5) and the length of the segment E'F' is 8 units.

Learn more about the geometric transformation here:

brainly.com/question/16156895

#SPJ1

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Umnica [9.8K]

Answer:

x=17

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Step-by-step explanation:

First plug in the numbers:

x-3=14 x-2=y

What does 3+14=? Well it should equal 17 if added properly.

So then this would be true 17-3=14.

Then if x-2=y you could write 17-2=15. Then y=15

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I need help writing an equation with x,y for the table.
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Read 2 more answers
Solve the following differential equation: (2x+5y)dx+(5x−4y)dy=0 *Hint: they are exact<br><br> C=.
Tpy6a [65]

Answer with Step-by-step explanation:

The given differential equation is

(2x+5y)dx+(5x-4y)dy=0

Now the above differential equation can be re-written as

P(x,y)dx+Q(x,y)dy=0

Checking for exactness we should have

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial y}=\frac{\partial (2x+5y)}{\partial y}=5

\frac{\partial Q}{\partial x}=\frac{\partial (5x-4y)}{\partial x}=5

As we see that the 2 values are equal thus we conclude that the given differential equation is exact

The solution of exact differential equation is given by

u(x,y)=\int P(x,y)dx+\phi(y)\\\\u(x,y)=\int (2x+5y)dx+\phi (y)\\\\u(x,y)=x^2+5xy+\phi (y)

The value of \phi (y) can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c

5 0
3 years ago
Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl
loris [4]

Answer:

The angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Given the following angles from the diagram;

m<5 = 55 degrees

m<9 = 80degrees

From the diagram

m<5 = m<1 = 55 degrees (corresponding angle)

m<1 + m<2 = 180 (sum of angle on a straight line)

Hence;

55 + m<2 = 180

m<2 = 180 - 55

m<2 = 125degrees

Also;

m<5 = m<8 = 55 degrees (vertically opposite angle)

m<9 = m<13 = 80degrees

m<13 + m<14 = 180

Hence;

80 + m<14 = 180

m<14 = 180 - 80

m<14 = 100 degrees

Hence the angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Step-by-step explanation:

7 0
2 years ago
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