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kotegsom [21]
3 years ago
14

The length of Chen’s office is 15.5 feet and the width is 7.8 feet. Use the formula P = 2ℓ + 2w to find the perimeter of the off

ice.
Enter your answer in the box.
Mathematics
2 answers:
Mamont248 [21]3 years ago
8 0

Answer:

46.6 feet

Step-by-step explanation:

Leto [7]3 years ago
6 0

Answer:

the perimeter is 46.6 feet

Step-by-step explanation:

The length of Chen’s office is 15.5 feet and the width is 7.8 fee

length =15.5

width = 7.8

Use the formula P = 2l + 2w

where 'l' is the length and 'w' is the perimeter

Plug in the values of length and width in the perimeter formula

P = 2l + 2w

P = 2(15.5) + 2(7.8)=46.6

So the perimeter is 46.6 feet

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How do i solve quadratics and quadratic formula
Murljashka [212]

<u>Step-by-step explanation:</u>

Multiply the first and last coefficient

Find a pair that has the product of ac (above) and the sum of b

Replace the b-term with the pair.

Divide the four terms into two-terms on the left side and two terms on the right side and factor out the common terms from each side.

This is reverse of the distributive property so the terms factored out (on the outside of the common term) combine to create a factor and the common term is the other factor.  

Set each factor equal to zero and solve for the variable.

***************************************************************************************

1a. Answer: a = 1/2      a = -1

2a² + 3a + 1 = 0      → ac=2, b = 3    → use 1, 2  (product is 2 & sum is 3)

2a² + 2a + 1a + 1 = 0

2a² + 2a     +1a + 1        = 0

2a(<u>a + 1</u>)      +1(<u>a + 1</u>)      = 0

(2a + 1)(a + 1) = 0

2a + 1 = 0       and         a + 1 = 0

       a = 1/2    and               a = -1

**************************************************************************************

1b. Answer: y = -5/2    y = -5

2y² + 5y - 25 = 0  → ac=-50, b = 5 → use 10, -5  (product is -50 & sum is -5)

2y² + 10y - 5y - 25 = 0

2y² + 10y      - 5y - 25        = 0

2y(<u>y + 5</u>)      -5(<u>y + 5</u>)      = 0

(2y - 5)(y + 5) = 0

2y + 5 = 0       and         y + 5 = 0

       y = -5/2    and               y = -5

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1c. Answer: y = 5     y = 1/2

2y² - 11y + 5 = 0  → ac=10, b = -11 → use -1, -10  (product is 10 & sum is -11)

2y² - 1y - 10y + 5 = 0

2y² - 1y       -10y + 5        = 0

y(<u>2y - 1</u>)      -5(<u>2y - 1</u>)      = 0

(y - 5)(2y - 1) = 0

y - 5 = 0       and         2y - 1 = 0

     y = 5       and               y = 1/2

4 0
3 years ago
WILL MARK BRAINLIEST IF CORRECT! ANSWER A, AND B, I GOT 5 MINS
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Answer:

dollar amount in decimal is 0.55

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8 0
2 years ago
Pre-cal help!! (See Attachment)
MAVERICK [17]
2cos(x) + 1 = 0

cos(x) = -\frac{1}{2}

The basic angle for 1/2 is 60°, and cosines are negative in the first and third quadrant.

So, you take 180° - 60° = 120° to get the angle in the first quadrant, and 180° + 60° = 240° to get the angle in the third quadrant.

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2 years ago
Which of the following is the solution set of x² + 8x + 12 = 0?
raketka [301]

Answer:

\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}

Step-by-step explanation:

Given:

x^{2} + 8x + 12 = 0

Solve for:

x

Solution:

Step 1: Select the formula to solve for x

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

      x^{2} + 8x + 12 = 0

<=>x^{2}  +  2x + 6x  + 12 = 0

<=>(x^{2} + 2x) + (6x + 12) = 0

<=>x(x + 2) + 6(x + 2) = 0

<=>(x + 2)(x + 6) = 0

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Hope this helps!

:)

4 0
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borishaifa [10]

Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

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41 - 50 ___________ 1 _________ 15

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Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

The next to highest frequency group has a frequency of 4 and the highest frequency of 6

Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16

5 0
3 years ago
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