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pentagon [3]
3 years ago
8

Which set of numbers could represent the lengths of the sides of a right triangle?16, 32, 368, 12, 166, 7, 85, 12, 13

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0
The answer is: 166!!!!!!

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A room that measures 12 feet by 9 feet needs new flooring. Wood flooring costs $2.70 per square foot. How much will it cost to c
Korvikt [17]
The answer is 291.60 because you multiply 12 x 9 which equals 108 then multiply 108 x 2.70 which equals 291.60
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3 years ago
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What is the percent change of 36;63
STatiana [176]
First, find the difference.
63-36=27
Then, divide by the original number.
27/36=0.75
Then, put it in percentage form.
75%
7 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Solve for x and y 10x + 7y = 1435
bearhunter [10]
Move all terms that don't contain x to the right side and solve.
x = -7y/10 + 718/5
6 0
3 years ago
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KLMN and PQRS are similar trapezoids. which side of PQRS corresponds to LM​
zhuklara [117]

Answer:

QR

Step-by-step explanation:

K<u>LM</u>N is in the same spot as P<u>QR</u>S

8 0
3 years ago
Read 2 more answers
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