Help... 25 pts and will give BRAINLIEST!

9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly

zavuch27 [327]

Answer:

$9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69$

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

$A=P(1+\frac{r}{n})^{nt}$ ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27$

10) Aubrey Daniel's case:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07$

11) As for Angelo, similarly to Alicia.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87$

12) Simpson's. For semiannual n=2

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95$

13) Jana Lacey amount:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69$

6 0

3 years ago

-1xf(-8)-4xg(4) pls help

KATRIN_1 [288]

Answer:

8f-16g

Step-by-step explanation:

-1×f(-8) -4×g(4)

-1×-8f -4×4g

8f -16g

Hopes this helps

pls mark brainliest

3 0

1 year ago

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Solve for y py+qy=-4y+8

Dahasolnce [82]

Answer:

y = 8/p+q+4.

Step-by-step explanation:

5 0

3 years ago

mauricio estimates that the first module of the project could be completed in as few as 15 days or could take as many as 25 days

4vir4ik [10]

Answer:

Most likely time, according to PERT (Program evaluation and review technique).

Step-by-step explanation:

PERT is "a statistical tool used in project management" (Program evaluation and review technique (2020), in Wikipedia), and it is commonly used with CPM (Critical Path Method) to manage projects.

Inside PERT, there are different defined times to accomplished an activity in a project, that is:

An optimistic time or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
A pessimistic time, a time quite the opposite to optimistic time.
A most likely time, or a time required to accomplished an activity if everything goes as expected or normally.
An expected time, an statistical estimation.

Considering the question, we have that the time when "the first module of the project could be completed":

"[...] in as few as 15 days" is the optimistic time.
"[...] or could take as many as 25 days" is the pessimistic time.
"[...] but most likely will require 20 days" is the most likely time.

As a result, the 20-day estimate is called the most likely time in the context of the PERT/CPM techniques.

3 0

3 years ago

Not sure if this is right.

finlep [7]

Answer:

I think your right :)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers