We can start by figuring out the axis of symmetry.
y = x² + 12x = x (x + 12)
So roots are x = -12 or 0
Therefore axis of symmetry is x = (-12 + 0) / 2 = -6
We got x-coordinate of vertex. Now plug in x=-6 to solve for y.
y = (-6)² + 12(-6) = 36 - 72 = -36
Therefore vertex is (-6, -36).
angles x y z are all acute because they are less than 90 degrees
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You need to give options for future reference
Answer:
-26
Step-by-step explanation:
5p + (-6)
Let p=-4
5(-4) + (-6)
Multiply
-20 +-6
Add
-26
3) y =
x + 3
Slope-intercept form is y = mx + b when m is the slope and b is the y-intercept
b = 2 (line hits y-axis at 2)
m =
so
and the line is negative, so 
Write our equation by putting the parts together, and we get:
y =
x + 3
4) y =
x - 1.67
Point slope form is y - y1 = m (x - x1) when y1 is the y coordinate of the point, m is the slope, and x1 is the x coordinate of the point
y - y1 = m (x - x1)
Finding the slope (same as above) results in 
<em>*aaaa I have to go, good luck, I do have the answer just no times to write out the steps, good luck and have a nice day!*</em>