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tiny-mole [99]
2 years ago
5

Weights attached to two suspended strings are

Physics
1 answer:
olga_2 [115]2 years ago
5 0
Answer: A) length of string.
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If earth had no atmosphere , would a falling object ever reach terminal velocity?
Bas_tet [7]
The right answer is no.
6 0
3 years ago
A basketball rolls without slipping (starting from rest) down a ramp. If the ramp is sloped by an angle of 4 degrees above the h
slavikrds [6]

Answer:

11.7 m/s

Explanation:

To find its speed, we first find the acceleration of the center of mass of a rolling object is given by

a = gsinθ/(1 + I/MR²) where θ = angle of slope = 4, I = moment of inertia of basketball = 2/3MR²

a = 9.8 m/s²sin4(1 + 2/3MR²/MR²)

  = 9.8 m/s²sin4(1 + 2/3)

  = 9.8 m/s²sin4 × (5/3)

  = 1.14 m/s²

To find its speed v after rolling for 60 m, we use

v² = u² + 2as where u = initial speed = 0 (since it starts from rest), s = 60 m

v = √(u² + 2as) = √(0² + 2 × 1.14 m/s × 60 m) = √136.8 = 11.7 m/s

4 0
3 years ago
El sistema energético que importancia tiene en el cuerpo
KiRa [710]

Answer:

De un modo más claro, los sistemas energéticos son los modos que tiene el organismo para suministrar ATP a los músculos. Como decimos, en todos los esfuerzos físicos es necesario contar con la cantidad suficiente de energía y esto viene determinado por la producción de ATP, el adenosin trifosfato.

5 0
3 years ago
Ch 14:42
Alisiya [41]

Answer:

1000m3

Explanation:

12000=mass*gravity, considerinh gravity 10

12000=mass*10 then mass=1200Kg

With density 1.2Kg/m3

1.2Kg ... 1m3

1200Kg ... 1000m3

End

4 0
3 years ago
A gamma ray photon has an energy of 0.91 GeV. (1 GeV = 109 eV.) What is the wavelength of the gamma ray in fm? (1 fm = 10-15 m)?
anastassius [24]

Answer:

\lambda=1.37 fm

Explanation:

The Planck Eistein relation, states that the energy of a photon is proportional to its frequency:

E=h\nu(1)

h is the Plank constant.The frequency of a photon is defined as the speed of light over its wavelength:

\nu=\frac{c}{\lambda}(2)

Replacing (2) in (1):

E=\frac{hc}{\lambda}\\\lambda=\frac{hc}{E}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{0.91*10^{9}eV}\\\\\lambda=(1.37*10^{-15}m)*\frac{1fm}{10^{-15}m}\\\\\lambda=1.37 fm

6 0
3 years ago
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