There is no need for tangential acceleration when moving in a circle at a constant speed.
<h3>What is centripetal acceleration?</h3>
centripetal acceleration refers to the speed at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is constantly changing, which causes a change in velocity, which results in an acceleration.
<h3>Which is an example of centripetal acceleration?</h3>
Centripetal acceleration occurs when you spin a ball on a string above your head. A car experiences centripetal acceleration when it is being driven in a circle. Additionally, a satellite in orbit around the Earth experiences centripetal acceleration.
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Answer
given,
weight of the oak board = 600 N
Weight of Joe = 844 N
length of board = 4 m
Joe is standing at 1 m from left side
vertical wire is supporting at the end.
Assuming the system is in equilibrium
T₁ and T₂ be the tension at the ends of the wire
equating all the vertical force
T₁ + T₂ = 600 + 844
T₁ + T₂ = 1444...........(1)
taking moment about T₂
T₁ x 4 - 844 x 3 - 600 x 2 = 0
T₁ x 4 = 3732
T₁ = 933 N
from equation (1)
T₂ = 1444 - 933
T₂ = 511 N
A proton has positive charge of 1, that is, equal but opposite to the charge of an electron. A neutron, like the name implies, is neutral with no net charge. The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons).
It is important to look at all the information's that are given in the question very closely. Let us write them write first.
Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
= 2</span>π (5/√2-1)
= <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span> = 2π(5/(√2+1))/(2-1) </span>
<span> = 10π(√2+1)
I hope that the procedure is clear enough for you to understand.</span>
