Answer:
Explanation:
The former is the case of constructive interference and the later case relates to destructive interference.
For listener, path difference is the separation of loudspeaker as listener is not standing in between the speaker.
If λ be the wave length
For constructive interference
19 = n λ
For destructive interference
29 = (2n+1) λ / 2
= n λ + λ / 2
= 19 + λ / 2
10 = λ / 2
λ = 20 cm
= 0. 20 m
There is no illustration of the problem provided but I'll attempt to provide an answer.
The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:
║E║ = ΔV/d
║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.
We are given the following values:
║E║= 10N/C
d = 3m
Plug these values in and solve for ΔV
10 = ΔV/3
ΔV = 30V
Answer: Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC.
Explanation:
Answer:
0.695s
Explanation:
From Hooke's law, the restoring force is given has
F = -ky .......1
Where F is the force, y is the spring displacement and k force constant of the spring.
Also recall,
F=mg ............ 2
Where m is the mass of object, g is the acceleration due to gravity.
Equating 1 and 2
Ky = mg
Given that g=9.8m/s2 , y is 3.4cm and g is 8g
K×3.4/100m =8/1000kg × 9.8m/s2
K= ( 0.008kg × 9.8m/s2 ) ÷ 0.034
K= 0.0784÷0.035
K=2.24N/m
Mass ofvthe second object is 25g =0.025kg
Period of oscillation T
T=2π√m/k
T=2×3.142√0.025/2.24
T=6.284√0.0111
T=0.659seconds
