All categories

3 years ago

El sistema energético que importancia tiene en el cuerpo

Physics

1 answer:

KiRa [710]3 years ago

5 0

Answer:

De un modo más claro, los sistemas energéticos son los modos que tiene el organismo para suministrar ATP a los músculos. Como decimos, en todos los esfuerzos físicos es necesario contar con la cantidad suficiente de energía y esto viene determinado por la producción de ATP, el adenosin trifosfato.

You might be interested in

How should variables be depicted on a graph?

nignag [31]

Answer:

D.) independent variable on the x-axis

Explanation:

Normally in an x-y plane, the value of x is taken as an independent variable, i.e. it is independent because it can assume any value (real number), while y depends on the value x. for example for the following equation.

y = x

Where:

x = independent value.

y = dependent value of x

This is the equation of a line, inclined with slope equal to 1.

4 0

3 years ago

Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!

Ainat [17]

The total electrostatic force on charge A is $28 \mu N$

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

$x_A = 0\\x_B = 10 m\\x_C = 20 m$

The magnitudes of the three charges are:

$q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C$

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

$F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N$

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0

3 years ago

1. Monique is nine weeks into her pregnancy, and she had an appointment with her doc tor today. She is very happy and excited be

djyliett [7]

Since Monique is able to hear the heartbeats of her baby, it's the Fetus stage of pregnancy when the body starts developing inside the womb.

Explanation:

The Fetus Stage of Pregnancy:

Once the 4th-7th weeks of pregnancy passed, the embryo start developing inside the womb of the mother and the respective symptoms reflects. This is the Fetus stage of pregnancy which occur in approximately around the 10th week of pregnancy.

In the fetus stage, the human body begins to develop inside the womb. In this phase, most of the organs are developed and the limbs starts to form firmly. The Fetus stage comes after the Embryo stage but usually, the transition varies according to the growth and circumstances of the atmosphere.

But, what is certain is that the mother can feel the impulse and heartbeats of the baby inside her womb which is an exciting and memorable feeling for her.

7 0

4 years ago

2) A traffic light of weight 100 N is supported by two ropes as shown. Let T1 and T2 are the tensions.

GarryVolchara [31]

Hi there!

We know that:

$\Sigma F_y = 0 \\\\\Sigma F_x = 0$

Begin by determining the forces in the vertical direction:

W = weight of traffic light

T₁sinθ = vertical component of T₁

T₂sinθ = vertical component of T₂

The ropes provide a horizontal force:

T₁cosθ = Horizontal component of T1

T₂cosθ = Horizontal component of T2

Thus:

0 = T₁cosθ - T₂cosθ

T₁cosθ = T₂cosθ

T₁ = T₂

Since the angles for both ropes are the same, we can say that:

T₁ = T₂

Sum the forces:

ΣFy = T₁sinθ + T₁sinθ - W = 0

2T₁sinθ = W

Now, we can begin by solving for the tensions:

2T₁sinθ = W

$T_1 = T_2 = \frac{W}{2sin\theta} = \frac{100}{2sin(37)} = \boxed{83.08 N}$

8 0

3 years ago

What is the thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm ?

Marizza181 [45]

The thinnest film (but not zero) that produces a strong reflection for green light with a wavelength of 500 nm is 200 nm.

The wavelength of mild, λ = 500 nm

= 500 x 10^-9 m

Refractive index of oil, n1 = 1.25

Refractive index of water, n2 = 1.33

The thickness of the movie, d =?

For a sturdy mirrored image, m = 1

Wavelength, λ= 2 n1 d / m

Thickness, d = λ m / 2 n1

= 500 x 10 -9 * 1 / ( 2 * 1.25 )

= two hundred x 10 -nine m

= 2 hundred nm.

Wavelength is the gap between the same factors (adjacent crests) within the adjacent cycles of a waveform signal propagated in space or alongside a wire. In wireless systems, this duration is usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength may be defined as the space between two successive crests or troughs of a wave. it is measured within the route of the wave.

Wavelength is the distance among two adjacent crests or troughs of a waveform signal propagated in space or along a wire. The wavelength of a wave is usually specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is inversely related to frequency.

Learn more about Wavelength here brainly.com/question/10750459

#SPJ4

3 0

2 years ago