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VikaD [51]
1 year ago
9

Expand and simplify 3(x-2) + 2(4x-1)

Mathematics
1 answer:
Zanzabum1 year ago
3 0

Answer:

11x-8

Step-by-step explanation:

3(x - 2) + 2(4x - 1) \\ multiply \: inside \: the \: bracket \\ 3x - 6 + 8x - 2 \\ 11x - 8

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Will mark brainless
iren2701 [21]

Answer:

Step-by-step explanation:

y = 3x + 2

6x – 2y = 10

Ryan’s answer:

I solved by adding the equations. The solution is .

y = 3x + 2 → 3x + y = 2

6x – 2y = 10 → 3x – y = 5

6x = 7

x =

6x – 2y = 10 → 6 – 2y = 10

7 – 2y = 10

–2y = –3

y = -

Jesse’s answer:

I used matrices. The solution is .

Mark’s answer:

I graphed the equations. The lines are parallel and do not intersect, so there is no solution.

6 0
2 years ago
Y =28547, 11504 is obese, what is the %
Damm [24]
Huh? What does that even mean lol
3 0
2 years ago
The population p (in millions) of Italy from 1990 through 2008 can be approximated by the model p=56.8e^o.oo15t , where t repres
dimulka [17.4K]

As we already have the model that describes the change of the population in Italy in terms of the years that have elapsed, we only have to replace the conditions that are requested in that equation.

Therefore to find the population of Italy in the year 2000 (t = 10 years)  substitute t = 10 in the equation and have:

p = 56.8e^{0.0015*10}\\

p=57.6584 million people

To find the population of Italy in 2008 (t = 18 years)

substitute t = 18 in the equation and have:

p=56.8e ^{0.0015*18}\\

p=58.3545 million people


To predict the population in Italy for 2015 and 2020 with this model, we substitute in the equation t = 25 and t = 30

t = 25

p=56.8e^{0.0015*25}

p=58.9704 million people


 t = 30

p=56.8e^{0.0015*30}

p=59.4144 million people

8 0
2 years ago
Write 4.83…. (The 3 repeats infinitely)as a mixed number
kogti [31]

Answer:

4\frac56

Step-by-step explanation:

\frac56=0.8 \dot{3}

\implies 4.8 \dot{3}=4\frac56

6 0
2 years ago
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Georgina wants to practice the piano for a two least 45 minutes tonight. Which of the following inequalities represents the situ
Anika [276]
Um i would love to help but i do t really understand
5 0
3 years ago
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