Since there are no figures given, I will give an example.
You are given a silo that is shaped as
a closed cylinder with a conical end. The diameter of the silo is 4 ft, the
length of the cylindrical part is 6 ft, and the entire length of the silo is
10.5 ft. Suppose that you are asked to find the total volume of
grains that can be stored in the silo.
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = πr²H
V of cylinder = π(4/2)²(6)
V of cylinder = 75.4 ft³
V of cone = πr²H/3
V of cone = π(4/2)²(4.5/3)
V of cone = 18.85 ft³
Total volume = 94.25 ft³
Answer:
answer is 1/8
Step-by-step explanation:
hope this helps
A square pyramid has 4 triangles and the square base.
Calculate the area of one triangle, multiply that by 4 then add the area of the base.
Area of triangle = 1/2 x base x height = 1/2 x 5 x 12 = 30 square yards.
30 x 4 = 120 square yards
Area of base = 5 x 5 = 25 square yards
Total = 120 + 25 = 145 square yards.
-2y>12x-42
y<21-6x
so a is true
