Graph the following exponential functions and determine the y-intercept, domain, range, and
1 answer:
The graph of the exponential function f(x) = 5(2)ˣ is as shown in the attached file.
<h3>How to draw the graph of an exponential Function?</h3>We want to draw the graph of the exponential function;
f(x) = 5(2)ˣ
At input of x = 0, we have;
f(x) = 5(2)⁰ = 5
At input of x = 1, we have;
f(x) = 5(2)¹ = 10
At x = -1, we have;
f(x) = 5(2)⁻¹ = 2.5
At x = -2, we have;
f(x) = 5(2)⁻² = 1.25
Read more about Graph of Exponential Function at; brainly.com/question/12940982
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Using the z-distribution, we have that:
a)
The hypothesis test is:
The p-value is of 0.0668.
The critical value is
b) Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.
Item a:
At the null hypothesis, it is <u>tested if the mean is of 7.4 minutes</u>, that is:
At the alternative hypothesis, it is <u>tested if the mean is lower than 7.4 minutes</u>, that is:
We have the <u>standard deviation for the population</u>, hence, the z-distribution is used.
The test statistic is given by:
The parameters are:
is the sample mean.
is the value tested at the null hypothesis.
is the standard deviation of the sample.
- n is the sample size.
For this problem, the values of the <em>parameters </em>are: .
Hence, the value of the <em>test statistic</em> is:
Using a z-distribution calculator, the p-value is of 0.0668.
Also using a calculator, considering a <u>left-tailed test</u>, as we are testing if the mean is less than a value, the critical value with a <u>significance level of 0.1</u> is of .
Item b:
Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.
You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918