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Salsk061 [2.6K]
2 years ago
7

Can somebody help me please

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
3 0

Step-by-step explanation:

yes its ans is (3,3) fast you have see in x axis then y axis .so according to this we write 3 which lies in x- axis and then another 3 which lies in y-axis.

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Mrs. Reyes asked 3 girls and 4 boys to help with a project. She had each student make 8 paper airplanes. ​
Mazyrski [523]

There are 3 girls & 4 boys.

Each student makes 8 paper airplanes.

Amount of paper airplanes created by girls: 3 x 8 = 24

Amount of paper airplanes created by boys: 4 x 8 = 32

Amount of paper airplanes created in all: 3(8) + 4(8) = 24 + 32 = 56

~

3 0
3 years ago
17. Find the ratio of the perimeter to the area of the square shown.<br> x + 3<br> x + 3
Serga [27]

Answer:

4x+12/x^2+9

Step-by-step explanation:

Perimeter

x+3+x+3+x+3+x+3

Area

(x+3)(x+3)

7 0
3 years ago
Can someone please help me factorize this one:<br><img src="https://tex.z-dn.net/?f=0.01y%20%7B%7D%5E%7B2%7D%20%20-%20%20%5Cfrac
Scorpion4ik [409]

First let us convert 0.01 into fraction:

\frac{y^{2}}{100}  -\frac{1}{4}

Now we convert 100 and 4 into perfect squares as follows:

(\frac{y}{10})^{2}-(\frac{1}{2})^{2}

Now we use the property of :

x^{2} -y^{2} =(x+y)(x-y)

(\frac{y}{10} +\frac{1}{2} ) (\frac{y}{10} -\frac{1}{2} )

4 0
3 years ago
I need to fine the height of a triangular pyramid and I already have the volume and Area
Keith_Richards [23]
I’m not sure, but i think that you have to take the volume equation, and plug in the other variables (volume, area) to find the height
6 0
3 years ago
What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
3 years ago
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