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uranmaximum [27]
3 years ago
15

Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r

eaction of 25 mL of 0.833 mol/L HC3H3O2 with excess NaHCO3 ?
Chemistry
1 answer:
Alenkasestr [34]3 years ago
5 0
<h2>1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3 </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}    

0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol

NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2

According to stoichiometry:

1 mole of HC_2H_3O_2 will give = 1 mole of CO_2

0.0208 moles of HC_2H_3O_2 will give =\frac{1}{1}\times 0.0208=0.0208 moles of CO_2

Mass of HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g

Thus 1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3

Learn more about molarity

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tensa zangetsu [6.8K]

The energy of the hydrogen atom will be -0.85 ev.

Ionization, also known as ionization, would be the phenomenon by which an atom or molecule gains or loses electrons to acquire a negative and positive charge, frequently in conjunction with those other chemical changes. Ions are the name for the electrically charged molecular or atom that results.

These chemicals are known as ionic compounds, with table salt serving as an example. Ionization would be the process of removing electrons from such an element as well as a molecule as well as the dissociation of an ionic material, such as salt, itself into the individual ions in a solution like water.

The energy of hydrogen atom will be calculated by using the formula:

E_{n} = -13.6 ev / n^{2}

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E_{4} = -13.6 ev / 4^{2}\\E_{4} = -13.6 ev  / 16\\E_{4} = -0.85 ev

Therefore, the energy of the hydrogen atom will be -0.85 ev.

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4 0
1 year ago
Which compounds are the Bronsted- Lowry bases in the equilibrium?
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