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2 years ago

Is this correct?

Mathematics

1 answer:

creativ13 [48]2 years ago

5 0

Yes I believe you are correct

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

2 years ago

Please i need help on this question im strugling

DerKrebs [107]

Answer:

1: 5

2: 5

3: 1.5

Step-by-step explanation:

6 0

3 years ago

36 + (12 - 8) + 2 × 5

ivanzaharov [21]

Answer:

Step-by-step explanation:

To answer this we need to use the PEMDAS strategy, first solve any questions in parentheses, next solve all multiplication and division problems from left to right. Next, solve all addition and subtraction problems from left to right.

36 + (12 - 8) + 2 × 5

36 + 4 + 2 x 5

36 + 4 + 10

40 + 10

6 0

2 years ago

Read 2 more answers

Figure ABC is to be translated to Figure A'B'C' using the rule (x, y) → (x−2, y+3). Triangle ABC on the coordinate plane with th

Gelneren [198K]

( 0, 8 ) → B

Apply the given rule to the coordinates of point B (2, 5 )

thus B' = ( 2 - 2, 5 + 3 ) = (0, 8 )