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puteri [66]
2 years ago
11

Is this correct?

Mathematics
1 answer:
creativ13 [48]2 years ago
5 0
Yes I believe you are correct
You might be interested in
Bottle A contains 4 ounces of water, which is 25% of the amount of water in Bottle B. How much water is there in Bottle B?
sveticcg [70]

Answer:

B=16 ounces

C=24 ounces

B=1/0.75=133%

Step-by-step explanation:

we have that

A≡0.25B (25%), if A=4 ounces  then B=4/0.25 = 16 ounces

C=1.5B (150%), if B=16 ounces then C=1.5*(16 ounces) = 24 ounces

D≡xB (?%), if D=12 ounces then x=12/16 = 0.75 ≡ 75%, but xB≡D ⇒ B≡D/x →

B≡12(1/0.75)= B=12*(1.333)→ B≅133%D

6 0
3 years ago
I will mark brainliesttt!
irinina [24]

Answer: 75 degrees

Step-by-step explanation: supplementary means 180 so you do 180-105 which is 75

6 0
3 years ago
1-sin^2x/sinx-cscx <br><br>How do I solve this problem? I keep getting the wrong answer.
Annette [7]

Answer:

-sinx

Step-by-step explanation:

a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1

with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x

so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx

it is also important to know that cscx is the same thing as 1/sinx

knowing this information, cscx can be replaced with 1/sinx

(cos^2x)/(sinx - 1/sinx)

now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....

cos^2x

---------------------

(sin^2x - 1)/sinx

notice how in the denominator it has sin^2x-1 which is equal to -cos^2x

so now it becomes:

cos^2x

--------------

-cos^2x/sinx

because we have a fraction over a fraction, we need to flip it

cos^2x          sinx

---------- * ----------------

1                  -  cos^2x

because the cos^2x can cancel out, it becomes 1

now the answer is -sinx

3 0
3 years ago
Consider the vector b⃗ b→b_vec with length 4.00 mm at an angle 23.5∘∘ north of east. What is the y component bybyb_y of this vec
Stells [14]

Answer:

  • \large\boxed {1.59 mm}

Explanation:

<u>1. Given vector:</u>

  • length: 4.00 mm = magnitude of the vector
  • angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)

<u>2. y-component</u>

The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.

  • sine (23.5º) = y-component / magnitude

  • y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.

  • \large\boxed{y-component = 1.59 mm}

7 0
3 years ago
How to find the coordinates?
zhenek [66]
The lower number of the fraction is the X value and since it's negative u go 3 to the right(if u loon at point T)and since it's a negative 4 on the top you go 4 down and if you would reverse it you would notice that 0|4 is 1 y value below the straight line so the coordinates are (3|5)
6 0
3 years ago
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