In a circle, the measure of an inscribed angle is half the measure of the intercepted arc.
∠BCD = arc BAD/2 ⇒ arc BAD = 2*∠BCD = 2*100 = 200°
arc BCD = 360° - arc BAD = 360° - 200° = 160°
∠d = arc BCD/2 = 160/2 =
80°
Answer:
468.4 meters
Step-by-step explanation:
Find the width of the rectangle.
The area of a rectangle is A=length*width. Substitute the values of length and area and solve for width.
A=length*width
8,400=140*width
60= width
Use the width of the rectangle to find the circumference of the semicircles. Since each semicircle is half of a circle, the perimeter of the two semicircles is equal to the circumference of one circle.
The circumference of a circle is equal to pid, where d is the diameter. The diameter of the semicircle is the same as the width of the rectangle.
So, the diameter is 60 meters. Substitute the diameter into the formula for the circumference and simplify using 3.14 for pi.
≈188.4
(2 times 140)+ 188.4
So, the perimeter of the track is 468.4 meters.
Answer:
D
Step-by-step explanation:
Answer:
All real number
Step-by-step explanation:
Is this ok
5/12 is close to 4/12
9/24 is also close to 4/12
2/3 is also close to 4/12
3/12 is also pretty close to 4/12
7/24 is also quite close to 4/12
Hope this helps :)