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Evgen [1.6K]
2 years ago
8

A sweet shop sells 150g of sweets for £1.32 Work out the cost of buying 475g of sweets​

Mathematics
2 answers:
matrenka [14]2 years ago
6 0

The cost of buying 475g of the sweets from the same company is; $4.18.

<h3>What is the cost of buying 475g of sweets?</h3>

According to the task content, it follows that the cost of buying 475g of sweets in the shop is required.

Since the shop sells 150g of sweets for £1.32, then it follows that 475g of sweets should cost;

= (475× 1.32)/150

= $4.18

Read more on ratios;

brainly.com/question/2914376

#SPJ2

kirza4 [7]2 years ago
5 0

Answer:

£4.18.

Step-by-step explanation:

150 g costs 1.32

1g         ..      1.32/150

475g    ..       (1.32/150) * 475 = £4.18.

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Read 2 more answers
Please help me with this math question!
barxatty [35]
1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>\sqrt[n]{3} =   3^{ \frac{1}{n} }.

The square root of 3 (\sqrt{3}) = 3 to the one-half power (3^{ \frac{1}{2} }).
The 5th root of 3 (\sqrt[5]{3}) = 3 to the one-fifth power (3^{ \frac{1}{5} }).

2) Now use the product of powers exponent rule to simplify:
This rule says a^{m} a^{n} = a^{m+n}&#10;. When two expressions with the same base (a, in this example) are multiplied, you can add their exponents while keeping the same base.

You now have (3^{ \frac{1}{2} })*(3^{ \frac{1}{5} }). These two expressions have the same base, 3. That means you can add their exponents:
(3^{ \frac{1}{2} })(3^{ \frac{1}{5} })\\&#10;= 3^{(\frac{1}{2} + \frac{1}{5}) }\\&#10;= 3^{\frac{7}{10}}

3) You can leave it in the form 3^{\frac{7}{10}} or change it back into a radical \sqrt[10]{3^7}

------

Answer: 3^{\frac{7}{10}} or \sqrt[10]{3^7}
6 0
3 years ago
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