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gladu [14]
2 years ago
9

What is the answer for this question?

Mathematics
1 answer:
UkoKoshka [18]2 years ago
8 0
1/4 if picking a 8 and 3/4 for a number greater then 5.
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What is the result when 212 is increased by 28%?
zhenek [66]

212 + 28% = <span>271.36</span>

<span>Hope it helps! :D</span>

5 0
3 years ago
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Factor a 3 - 3 + 3a 2 - a.
Troyanec [42]
(a - 1)(a + 1)(a + 3)
5 0
3 years ago
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The product of a number and four, increased by 5.
german
I’m pretty sure the answer is 4x+5
3 0
1 year ago
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Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
FromTheMoon [43]

Answer:

The Taylor series is \ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

The radius of convergence is R=3.

Step-by-step explanation:

<em>The Taylor expansion.</em>

Recall that as we want the Taylor series centered at a=3 its expression is given in powers of (x-3). With this in mind we need to do some transformations with the goal to obtain the asked Taylor series from the Taylor expansion of \ln(1+x).

Then,

\ln(x) = \ln(x-3+3) = \ln(3(\frac{x-3}{3} + 1 )) = \ln 3 + \ln(1 + \frac{x-3}{3}).

Now, in order to make a more compact notation write \frac{x-3}{3}=y. Thus, the above expression becomes

\ln(x) = \ln 3 + \ln(1+y).

Notice that, if x is very close from 3, then y is very close from 0. Then, we can use the Taylor expansion of the logarithm. Hence,  

\ln(x) = \ln 3 + \ln(1+y) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{y^n}{n}.

Now, substitute \frac{x-3}{3}=y in the previous equality. Thus,

\ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

<em>Radius of convergence.</em>

We find the radius of convergence with the Cauchy-Hadamard formula:

R^{-1} = \lim_{n\rightarrow\infty} \sqrt[n]{|a_n|},

Where a_n stands for the coefficients of the Taylor series and R for the radius of convergence.

In this case the coefficients of the Taylor series are

a_n = \frac{(-1)^{n+1}}{ n3^n}

and in consequence |a_n| = \frac{1}{3^nn}. Then,

\sqrt[n]{|a_n|} = \sqrt[n]{\frac{1}{3^nn}}

Applying the properties of roots

\sqrt[n]{|a_n|} = \frac{1}{3\sqrt[n]{n}}.

Hence,

R^{-1} = \lim_{n\rightarrow\infty} \frac{1}{3\sqrt[n]{n}} =\frac{1}{3}

Recall that

\lim_{n\rightarrow\infty} \sqrt[n]{n}=1.

So, as R^{-1}=\frac{1}{3} we get that R=3.

8 0
3 years ago
Dimitri wants to measure the height of the palm tree. He lines himself up with the palm tree's shadow so that the tip of his sha
kompoz [17]

Answer:

24 feet

Step-by-step explanation:

First, I used the proportion method to set up the numbers. I used x for the height of the tree.

x/45 = 6/11.25

Notice that the x and the 6 are both the heights of the tree and Dimitri and that they are both on the top of the fractions.

45 and 11.25 are the lengths of the shadows and they are both on the bottom of the fractions.

Next, I did 6 times 45 and got 270. Then I did 270 divided by 11.25 and got 24.

You're welcome!     :)

8 0
3 years ago
Read 2 more answers
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