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Ivenika [448]
2 years ago
6

Sonji bought a combination lock that opens with a four-digit number created using the digits 0 through 9. The same digit cannot

be used more than once in the combination.
If Sonji wants the last digit to be a 7 and the order of the digits matters, how many ways can the remaining digits be chosen?

84
504
3,024
60,480
Mathematics
1 answer:
Alex777 [14]2 years ago
8 0

Answer:

504 combos

Step-by-step explanation:

Cannot use digits twice and last is '7'

 9 digits for first place choice  

     8 digits for second place

         7 digits for third place

               only  '7' for fourth place       9 x 8 x7 = 504 combos

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3 years ago
The scale on the architectural plans for a new house is 1 in. equals 4 ft. Find the length and width (in ft) of a room that meas
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Step-by-step explanation:

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Therefore, if the length of the room as measured on the drawing is 6 inches, the actual length of the room will be

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8 0
3 years ago
Urgent help needed...............
andreyandreev [35.5K]

Answer:

Option b is correct

\{x | x \neq \pm 7, x\neq 0\}.

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

h(x) = \frac{9x}{x(x^2-49)}

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

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By zero product property;

x = 0 and x^2-49= 0

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Therefore, the domain of the given function is:

\{x | x \neq \pm 7, x\neq 0\}

7 0
3 years ago
Read 2 more answers
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