Answer:
about 16°
Step-by-step explanation:
Make sure your calculator is in degree mode.
Drawing the right triangle, we see that the shorter leg is 34 meters, and the longer leg is 122 meters. So the angle of elevation is:


Answer: 1.08t and (1+8/100)
Step-by-step explanation:
I just did this question

keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
Step-by-step explanation:
Collinear points have the same gradient
find the gradient(slope) between AB first

Find the one for BC

Find the gradient between AC now

YOUR LAST STATEMENT NOW WILL BE
POINTS A,B AND C ARE COLLINEAR SINCE THE GRADIENTS BETWEEN THEM IS THE SAME!!!
This is in its simplest form.
There are no like terms to an operation