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2 years ago

12

Evaluate 17 + 70/x when x = 14.

1 answer:

kipiarov [429]2 years ago

5 0

Answer:

34.5

Step-by-step explanation:

17 + 70/x when x = 14.

substitute x for 14

17 + 70/4

17 + 17.5

34.5

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Write an expression that equals 24 include an exponent

pogonyaev

Answer:

(4^2)+8

4 times 4 is 16,

16 plus 8 is 24.

3 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Describe how you could use algebraic operations to solve the equation 1 = -3x + 4

Anna11 [10]

Answer:

x=1

Step-by-step explanation:

3x=4-1

3x=3

x=1

3 0

2 years ago

What is the value of g(0)<br> a. 1<br> b. 0<br> c. 8<br> d. 4

uysha [10]

Answer:

c. 8

Step-by-step explanation:

1) $g(x)=8(\frac{1}{2} )^{x}$

2) $g(0)=8(\frac{1}{2} )^{0}$

3) $g(0)=8*1$

4) $g(0)=8$

4 0

2 years ago

Let the function f be continuous and differentiable for all x. Suppose you are given that f(−1)=−3, and that f'(x) for all value

Monica [59]

Answer:

Step-by-step explanation:

By MVT,

$f'(c) = \frac{f(5)-f(-1)}{5-1}$

$4f'(c)= f(5) + 3\rightarrow f(5) = 4f'(c) - 3$

Moreover, $f'(x)\leq 4~~~~~~ \forall x,$

$f(5) \leq 16 - 3 =13$

Hence the largest possible value of f(5) is 13

8 0

2 years ago