If the two ends of this triangular right prism are equilateral triangles. The surface area of the prism is 74cm.
<h3>Surface area</h3>
Using this formula
A=bh+L(S1+S2+S3)
Where:
L=5cm
b=4cm
h=3.5cm
S1=4cm
S2=4cm
S3=4cm
Let plug in the formula
A=4(3.5)+5(4+4+4)
A=14+5(12)
A=14+60
A=74 cm
Therefore the surface area of the prism is 74cm.
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Answer:
dependent variable: circles drawn
independent: time
the independent variable is what you control, which was the time spent. the amount of circles you were able to draw <em>depended</em> on the amount of time you had, so it was the dependent variable.
part 2:
if you drew circles at the same rate
0-0
1-29
2-58
3-87
4-116
hope that helped! lemme know if you need more
Answer:
Yes sas
Step-by-step explanation:
Answer:
in explanation
Step-by-step explanation:
The canary, the seagul, and the crow, All have both checkmarkes that shows that they Can fly AND they are birds (so B)
Bro this is easy you dont need Brainly for this just read it carefully and look at the graph.
Answer: Choice B
a_n = 10(1/2)^(n-2) is the nth term
average rate of change = -35/3
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Explanation:
Each time x increases by 1, y is cut in half. For instance, going from (2,10) to (3,5) shows this.
If we want to go in reverse, decreasing x by 1 will double the y value. So (1,20) is another point and (0,40) is another. We'll be using (0,40) and (3,5) because we want the average rate of change from x = 0 to x = 3. I'm using x in place of n here.
Use the slope formula to find the slope of the line through (0,40) and (3,5)
m = (y2-y1)/(x2-x1)
m = (5-40)/(3-0)
m = -35/3
The negative slope means the line goes downhill as you read it from left to right. The average rate of change from n = 0 to n = 3 is -35/3
The nth term of this geometric sequence is 20(1/2)^(n-1) since 20 is the first term (corresponds to n = 1) and 1/2 is the common ratio. Your teacher has done a bit of algebraic manipulation to change the n-1 into n-2. This means the 20 has to change to 10 to counterbalance.
In other words, 20(1/2)^(n-1) is equivalent to 10(1/2)^(n-2) when n starts at n = 1.
