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Anika [276]
3 years ago
5

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

e numbers y of cell sites from 1985 through 2014 can be modeled by
y = 340,110/
1 + 377e−0.259t
where t represents the year, with
t = 5 corresponding to 1985.
Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006
Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

y = \frac{340110}{1 + 377e^{-0.259t}}

Solving (a): 1998

Year 1998 means that:

t =1998 -  1980

t =18

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*18}}

y = \frac{340110}{1 + 377e^{-4.662}}

y = \frac{340110}{1 + 3.562}

y = \frac{340110}{4.562}

y = 74553 --- approximated

Solving (b): 2003

Year 2003 means that:

t = 2003 -  1980

t =23

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*23}}

y = \frac{340110}{1 + 377e^{-5.957}}

y = \frac{340110}{1 + 0.976}

y = \frac{340110}{1.976}

y = 172120 --- approximated

Solving (c): 2006

Year 2006 means that:

t = 2006 -  1980

t =26

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*26}}

y = \frac{340110}{1 + 377e^{-6.734}}

y = \frac{340110}{1 + 0.4485}

y = \frac{340110}{1.4485}

y = 234802 --- approximated

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ankoles [38]

Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

Constant: π = 22/7.

Substitute these values into equation 1

A' = [(22/7)×4²]-3²

A' = 50.29-9

A' = 41.29 cm²

Hence the area of the shaded portion is 41.29 cm²

8 0
3 years ago
Tanner walks 42 kilometers each morning. How many meters does he walk each morning?
hichkok12 [17]

Answer:

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3 0
2 years ago
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zhannawk [14.2K]
I’m pretty sure it’s 82
6 0
2 years ago
2
GaryK [48]

Answer:

B_2=4\pi r^2

see the explanation

Step-by-step explanation:

we know that

The area of the base of a cylinder is given by the formula

B=\pi r^{2}

where

r is the radius of the circular base

If the radius is doubled

then

r=2r

The new base area is

B_2=\pi (2r)^{2}

B_2=4\pi r^2

so

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therefore

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3 years ago
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Answer:

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Step-by-step explanation:

i think 1.6.

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8 0
3 years ago
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