We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer: x>-1
Step-by-step explanation: I know this because I solved this equation. I know that is not a good explanation but I know it is right.
Answer:
i think point c GL
Step-by-step explanation:
Answer:
x<4 and x>1
Step-by-step explanation:
1) 3x-4<8
Add 4 to both sides first to isolate x.
3x-4<8
<u>+4 +4</u>
3x<12
Divide both sides by 3.
3x<12
<u>/3 /3</u>
x<4
2) 2x+2>4
Subtract both sides by 2 to isolate x.
2x+2>4
<u>-2 -2</u>
2x>2
Divide both sides by 2.
2x>2
<u>/2 /2</u>
x>1
Hope this helped!! Have an amazing day :3