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melisa1 [442]
2 years ago
12

A teacher wants to know if burning a scented candle affects students’ performance on pop quizzes. In the experiment, there will

be a treatment group and a control group each taking their quizzes in a room that either does or does not have a scented candle burning. On a randomly chosen day, the first 15 students who arrive to class will be the control group while the last 15 students who arrive will be the treatment group. Which statement best describes the composition of the groups? The characteristics of the two groups should be roughly equivalent because both groups have 15 students. The characteristics of the two groups should be roughly equivalent because the students were split into groups on a randomly chosen day. The characteristics of the two groups might not be roughly equivalent because the students were not labeled and given a random number to place them in one of the groups. The characteristics of the two groups might not be roughly equivalent because students who arrive around the same time might be friends and have similar preferences for scented candles.
Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
6 0

The characteristics of the two groups might not be roughly equivalent because the students were not labeled and number wasn't given.

<h3>What is Composition? </h3>

This is the process which involves combining different parts in other to form a whole.

The student were not labeled and number wasn't given to place them in one of the groups will best describe their roughly equivalent composition hence option C was chosen.

Read more about Composition here brainly.com/question/9464122

#SPJ1

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When investigating times required for drive-through service, the following results (in seconds) were obtained: Restaurant A 120
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Answer:

Step-by-step explanation:

Restaurant A data in ascending order : 67 68 72 89 96 97 120 124

Restaurant B data in ascending order : 49 56 76 78 95 98 115 126

                                    <em>Restaurant A</em>

  • Mean         = \frac{67+68+72+89+96+97+120+124}{8} =  91.625
  • Median      = Since there are even number of observations so,  

                           =   \frac{4^{th}obs + 5^{th}obs  }{2} = \frac{89+96}{2} = 92.5

  • Mid range  = \frac{Highest Value-Lowest Value}{2} = \frac{124-67}{2} = 28.5
  • Range         = Highest value - Lowest value = 124 - 67 = 57
  • Variance    = \frac{\sum (X_i - \mu )^{2}}{N-1} ,where Xi are sample values and \mu is mean

       Solving above equation we get, variance = 493.982

  • Standard Deviation = \sqrt{variance} = 22.226

                                     <em>Restaurant B</em>

  • Mean        = \frac{49+56+76+78+95+98+115+126}{8} = 74.375
  • Median    = Since there are even number of observations so,

                          = \frac{4^{th}obs + 5^{th}obs  }{2} = \frac{78+95}{2} = 86.5

  • Mid Range =  \frac{Highest Value-Lowest Value}{2} = \frac{126-49}{2} = 38.5
  • Range         = Highest value - Lowest value = 126 - 49 = 77
  • Variance     =  \frac{\sum (X_i - \mu )^{2}}{N-1} ,where Xi are sample values and \mu is mean

                            = 727.982

  • Standard Deviation = \sqrt{variance} = 26.981

Now comparing the results of two restaurants we conclude that:

  1. Restaurant A on an average takes more time for drive-through service than Restaurant B.
  2. Median time for Restaurant A is also more than Restaurant B.
  3. Restaurant B has more variation in time taken for drive through service as the variance & standard deviation of Restaurant B is more than A.
  4. There is more spread in the time data for Restaurant B as it has more range than A.
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