Match the match sentences that count on and back by tens.

Help!!!

Artyom0805 [142]

Answer:

C: y+7=2/5(x+4)

Step-by-step explanation:

The point-slope form of the equation of a line with slope m through point (h, k) is ...

y -k = m(x -h)

You are given m=2/5 and (h, k) = (-4, -7). Put these numbers into the form and simplify the signs:

y -(-7) = 2/5(x -(-4)) . . . . . numbers put into the form

y +7 = 2/5(x +4) . . . . . . . signs simplified . . . . matches choice C

5 0

3 years ago

The area of a room is 55.929 square meters if its width is 5.43 meters, what is its length

Anna007 [38]

Answer:

10.3m

Step-by-step explanation:

area of a rectangle is width times length, so you have to rearrange the equation

55.929 ÷ 5.43 = 10.3

3 0

3 years ago

Read 2 more answers

Candle food is on sale for 20% of the original price what is the discount of the key if the original price is $1.35

Evgesh-ka [11]

Hi there!

To calculate a discount or a mark-up in the price of a retail item, you need to multiply the given price of the item by the percentage, like so:

1.35 × 0.2 = 0.27

Then you add or subtract as necessary. In your case you would subtract since you are trying to find a discount price.

1.35 - 0.27 = 1.08

So the final price of the product after the discount is $1.08

Your friend, ASIAX

5 0

3 years ago

Y varies directly as x. Y=42 when x=6. Find the value of y when x =15.

pentagon [3]

Answer:

y=120

Step-by-step explanation:

Y varies directly as x is written as

$y \alpha x$

introducing a constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

making k the subject by dividing through by 6

$\frac{48}{6} = \frac{6k}{6}$

k=48/6

k=8

put the value of k in the expression y=kx

y=8x

from the question,the value of y when x=15 is given by

y=8×15

y=120.

4 0

3 years ago

Find a power series representation of e^x sin(x)

liberstina [14]

The Taylor series is defined by:
$f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n$

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
$f^n (x) = e^x g^{n-1} (x) + e^x g^n (x) \\ g^0 (x) = sin x$

Do this successively to n = 6.
$f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x) \\ f^3 (x) = e^x(2cos x - 2sin x) \\ f^4 (x) = e^x (-4 sin x) \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)$

Plug in x=0 and sub into taylor series:
$e^x sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...$

If more terms are needed simply continue the recursive derivative formula and add to taylor series.

6 0

3 years ago