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3 years ago

The grid represents 1 whole. Shade the grid to the model 0.3.

Mathematics

1 answer:

Triss [41]3 years ago

8 0

Answer:

where is the grid? I would help if you have more info

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effrey typed 110 words in 2 2/3 minutes. At this rate, how many words can he type in 4 1/4 minutes?

MakcuM [25]

First, you find the rate at which Jeffery types.

110 divides by 2.75. This makes 40.

Then to find the amount of words he types in 4.25 minutes,

40 x 4.25. This makes 170.

So Jeffery can type 170 words in 4 1/4 minutes.

Click to let others know, how helpful is it

6 0

3 years ago

F(x)= 2x^2 + k/x point of inflection at x=-1 then value of k is

Nady [450]

I think it isss 2 :)))

4 0

4 years ago

Please hurry it’s missing

boyakko [2]

Answer:

exact form 77/8

decimal form 9.625

mixed number form 9 5/8

5 0

3 years ago

If w = 5 cos (xy) − sin (xz) and x = 1/t , y = t, z = t^3 ; then find dw/dt

Scrat [10]

In this question, we find the derivatives, using the chain's rule.

Doing this, the derivative is:

$\frac{dw}{dt} = \frac{5}{t}(\sin{1} - \cos{1}) - 2t\cos{t^2}$

Chain Rule:

Suppose we have a function $w(x,y,z), x = x(t), y = y(t), z = z(t)$ , and want to find it's derivative as function of t. It will be given by:

$\frac{dw}{dt} = \frac{dw}{dx}\frac{dx}{dt} + \frac{dw}{dy}\frac{dy}{dt} + \frac{dw}{dz}\frac{dz}{dt}$

Thus, we have to find the desired derivatives, which are:

w of x:

$\frac{dw}{dx} = -5y\sin{(xy)} - z\cos{(xz)}$

Considering $x = \frac{1}{t}, y = t, z = t^3$

$\frac{dw}{dx} = -5t\sin{(1)} - t^3\cos{(t^2)}$

w of y:

$\frac{dw}{dy} = -5x\cos{(xy)}$

Considering $x = \frac{1}{t}, y = t$

$\frac{dw}{dy} = -\frac{5}{t}\cos{1}$

w of z:

$\frac{dw}{dz} = -x\cos{(xz)}$

Considering $x = \frac{1}{t}, z = t^3$

$\frac{dw}{dz} = -\frac{1}{t}\cos{(t^2)}$

Derivatives of x, y and z as functions of t:

$\frac{dx}{dt} = -\frac{1}{t^2}$

$\frac{dy}{dt} = 1$

$\frac{dz}{dt} = 3t^2$

Derivative of w as function of t.

Now, we just replace what we found into the formula. So

$\frac{dw}{dt} = \frac{dw}{dx}\frac{dx}{dt} + \frac{dw}{dy}\frac{dy}{dt} + \frac{dw}{dz}\frac{dz}{dt}$

$\frac{dw}{dt} = (-5t\sin{(1)} - t^3\cos{(t^2)})(-\frac{1}{t^2}) - (\frac{5}{t}\cos{1}) - (\frac{1}{t}\cos{(t^2)})3t^2$

Applying the multiplications:

$\frac{dw}{dt} = \frac{5}{t}\sin{1} + t\cos{t^2} - \frac{5}{t}\cos{1} - 3t\cos{t^2}$

Applying the simplifications:

$\frac{dw}{dt} = \frac{5}{t}(\sin{1} - \cos{1}) - 2t\cos{t^2}$

Which is the derivative.

For more on the chain rule, you can check brainly.com/question/12795383

8 0

3 years ago

Sean drank a slushy as fast as he could.

Ray Of Light [21]

Answer:

600 cause at the start he had 600 ML in the cup, and as the seconds went by, he was drinking it so it went down. That means the start (0 seconds) had 600 ML in it.

3 0

3 years ago

Read 2 more answers