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Alex_Xolod [135]
3 years ago
11

Angel bought 8 oranges and 11 Apples for a total $15.22. He knows that each orange costs 0.50 and reasoned that each Apple must

cost a little more than $1.00. Is this guess reasonable? why or why not?
Mathematics
2 answers:
Marysya12 [62]3 years ago
4 0
Yes, it is fairly reasonable... if you round it..

however, if you want exact calculations, then it might not be so reasonable, because it will go over the total amount

so if you round it, then yes it is fairly reasonable
KatRina [158]3 years ago
4 0
We know that Angel bought 8 oranges and 11 apples, so let o represent oranges and a represent apples
8o+11a=15.22
8(0.5)+11a=15.22
4+11a=15.22
Subtract 4 for both side
11a=11.22
Divided 11 for both side
a=$1.02. As a result, this reasonable is correct according to my math calculations. Hope it help!
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If 4 + 5x = 11 + 4x, then 2x =____?
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Answer is 6
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As x =6
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8 0
3 years ago
for a class project, a political science student at a large university wants to estimate the percent of students that are regist
nekit [7.7K]

Answer:

90% confidence interval for the true percent of students that are registered voters is [0.56 , 0.64].

Step-by-step explanation:

We are given that for a class project, a political science student at a large university wants to estimate the percent of students that are registered voters.

He surveys 500 students and finds that 300 are registered voters.

Firstly, the pivotal quantity for 90% confidence interval for the true proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students who are registered voters = \frac{300}{500} = 0.60

           n = sample of students = 500

           p =  true percent of students

<em>Here for constructing 90% confidence interval we have used One-sample z proportion test statistics.</em>

So, 90% confidence interval for the true proportion, p is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90  {As the critical value of z at 5%

                                            level of significance are -1.6449 & 1.6449}  

P(-1.6449 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.6449) = 0.90

P( -1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> =[\hat p-1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.6449 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.60-1.6449 \times {\sqrt{\frac{0.60(1-0.60)}{500} } } , 0.60+1.6449 \times {\sqrt{\frac{0.60(1-0.60)}{500} } } ]

 = [0.56 , 0.64]

Therefore, 90% confidence interval for the true percent of students that are registered voters is [0.56 , 0.64].

Interpretation of the above confidence interval is that we are 90% confident that the true percent of students that are registered voters will lie between 0.56 and 0.64.

6 0
3 years ago
Pls help me with this problem
Ratling [72]

Answer:

2

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 +b^2 = c^2  where a and b are the legs and c is the hypotenuse

a^2 + (2.1)^2 = (2.9)^2

a^2 +4.41=8.41

a^2 = 8.41-4.41

a^2 =4

Take the square root of each side

sqrt(a^2)=sqrt(4)

a=2

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The special angles pairs that are formed are identified below.

<h3>What are the Special Angle Pairs?</h3>

Special angle pairs are formed by a transversal and the parallel lines it cuts across.

Based on the image given, the special angle pairs are given as follows:

Corresponding angles:

∠1 and ∠5

∠4 and ∠8

∠2 and ∠6

∠3 and ∠7

Alternate interior angles:

∠3 and ∠5

∠4 and ∠6

Consecutive interior angles:

∠4 and ∠5

∠3 and ∠6

Learn more about special angles pair on:

brainly.com/question/13801876

#SPJ1

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Step-by-step explanation:

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