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2 years ago

I the equation 3x^2+6x=12, the value of c is?

Mathematics

1 answer:

ozzi2 years ago

4 0

Answer:

c = -12

Step-by-step explanation:

Quadratic Standard Form: ax² + bx + c

Step 1: Write equation

3x² + 6x = 12

Step 2: Subtract 12 on both sides

3x² + 6x - 12 = 0

Here, we have the standard form of the quadratic. We see that our c = -12

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Roman55 [17]

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2 years ago

3(4a + 5) - 6a. Please answer this question if correct I will mark brainest.

mr Goodwill [35]

Answer:

6a + 15

Step-by-step explanation:

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2 years ago

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8x to the 2nd power +2x-3=0

Papessa [141]

Answer:

x= 1/2 and -3/4

Step-by-step explanation:

By using factorization, we can solve this equation.

8x^2+2x-3=0

Factor:

(2x-1)(4x+3)=0

Solve:

2x-1=0

2x=1

x=1/2

Solve again:

4x+3=0

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Hope this helped

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2 years ago

In a certain Algebra 2 class of 27 students, 18 of them play basketball and 16

Bogdan [553]

Answer:

<em>The probability is 0.89 or 89%</em>

Step-by-step explanation:

<u>Probability</u>

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

$\displastyle p=\frac{24}{27}$

Simplifying:

$\displastyle p=\frac{8}{9}=0.89$

The probability is 0.89 or 89%

6 0

2 years ago

What are the possible numbers of positive, negative, and complex zeros of f(x) = x6 + x5 + x4 + 4x3 − 12x2 + 12?

gladu [14]

As per Descartes Theorem, a polynomial of degree n (n is the highest exponent of a polynomial) has n roots (or number of zeros) be it positive, negative, real or complex.

in f(x) = x⁶ + x⁵ + x⁴ + 4x³ − 12x² + 12, the highest degree is 6, then it has
a total of 6 zeros, positive, negative, real or complex.

5 0

2 years ago

Read 2 more answers