Let time be x distance be y
Put value in eq(2)



Put it in eq(1)
Answer:
<u>Problem A</u>
5 * 5 * x * x * x

<u>Problem B</u>
8 * 8 * 8

<u>Problem C</u>
4 * 4 * 4 * x * x * x * x

Answer:
(x-4)(x+11)
Step-by-step explanation:
(x-4)(x+11)
x^2-4x+11x-44
x^2+7x-44
Ding Dong!
Answer:
(a) what is the sample space for this chance process?
If we toss a coin three times then there are total
outcomes
The sample space associated with the given chance process is:

(b) what is the assignment of probabilities to outcomes in this sample space?
Since the given sample space has eight outcomes and we know that a fair coin is tosses three times. Therefore, the probability of all the events mentioned in the given sample space is same. Hence we have:
