If the width is 28 inches, then divide that by 4 and you get 7. You multiply that by 5 to get the length. That would be 35. Just to check, you know that the width 28 and length 35 are in ratio 4:5 if you divide by 7. The perimeter would be 2(35+28)=63*2=126. So the perimeter is 126. The area would be 35*28 which is 980. To sum up, the answers are as follows.
Length: 35 in
Perimeter: 126 in
Area: 980 inches squared.
A of trapezium = ((a+b)/2)(h)
A = ((10+10+4)/2)(8)
A = (24/2)(8)
A = 12(8)
A = 94
The area is 94ft²
Answer:
the answer is a 2/3 change(when simplified) that there will be a number 4 or smaller will there is a 1/3 changed(when simplified) that it will land high than 4
Step-by-step explanation:
The area of the rectangle that has a perimeter of 44 in is calculated as: 117 in².
<h3>What is the Area and Perimeter of a Rectangle?</h3>
Area = length × width
Perimeter = 2(length + width).
Given the following:
- Width = w in.
- Length = w + 4 in
- Perimeter of the rectangle = 44 in.
Therefore:
2(w + 4 + w) = 44
Solve for w
2(2w + 4) = 44
4w + 8 = 44
4w = 44 - 8
4w = 36
w = 9
Width of the rectangle = w = 9 in.
Length = w + 4 = 9 + 4 = 13 in.
Area of the rectangle = 13 × 9 = 117 in².
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