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Answer:
diagonal = = 12.8 inches (to the nearest tenth of an inch)
Step-by-step explanation:
As shown in the diagram attached to this solution:
Let the Length of the rectangular board = a
Let the width = b
Let the diagonal = d
where:
a = 10 inches
b = 8 inches
d = ?
Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:
(hypotenuse)² = (Adjacent)² + (Opposite)²
d² = 10² + 8²
d² = 100 + 64
d² = 164
∴ d = √(164)
d = 12.806 inches
d = 12.8 inches (to the nearest tenth of an inch)
<em>N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.</em>
9 longer sticks were used.
This is how i get it.
1. change m to cm, 1m =100cm
2. add both together, divide by 16 =8.125. Which means 1 of the stick should more than 8, and 1 of the other stick should be less than 8
3. substitute the equation
4.(55 x 7)+(75 x 9) =1060
This is how i get it.
1. change m to cm, 1m =100cm
2. add both together, divide by 16 =8.125. Which means 1 of the stick should more than 8, and 1 of the other stick should be less than 8
3. substitute the equation
4.(55 x 7)+(75 x 9) =1060